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Marizza181 [45]
2 years ago
5

Y=x^2+3x-4 y=3x+5 what does x and y equal

Mathematics
1 answer:
Rom4ik [11]2 years ago
4 0

Answer:

y = x^2+3x-4 y=3x+5

(3, 14)

Step-by-step explanation:

hope this helps and have a nice day!! :)

And also you should try to use Desmos calculator it really helps with these problem/ equations!! you just have to put y = x^2+3x-4 then press enter and on the second one you put  y=3x+5 and then it shows you a graph and plus the answer!! :))

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Alex777 [14]
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3 years ago
A person standing at the edge of a cliff throws a rock upward from a height of 180ft above ground level with an initial velocity
taurus [48]

Answer: 8.73 ft/s

Step-by-step explanation:

We have the following equation that models the motion of the rock:

h(t)=-16t^{2}+64t+180

Where h(t) is the height of the rock at a time t.

Now, if  h(t)=48 ft we can find t and then the velocity of the rock at that height:

48=-16t^{2}+64t+180

Rearranging the equation:

-16t^{2}+64t+132=0

Multiplying the equation by -1:

16t^{2}-64t-132=0

Solving with the quadratic formula t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}  , where a=16, b=-64, c=-132 .

t=\frac{-(-64)\pm\sqrt{(-64)^{2}-4(16)(-132)}}{2(16)}

Choosing the positive result of the equation:

t=5.5 s  

Since velocity V is defined as the traveled distance h(t) in a given time t, we have:

V=\frac{h(t)}{t}

V=\frac{48 ft}{5.5 s}

V=8.727 ft/s \approx 8.73 ft/s This is the velocity of the rock at the height of 48 feet

7 0
3 years ago
Find the measures of angles 1-10
Leviafan [203]

Answer:

1) 78

2) 28

3) 74

4) 28

5) 74

6) 106

7) 74

8) 74

9) 78

10) 78

5 0
3 years ago
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3 0
3 years ago
Given the function f(x)=4|x-5|+3 for what values of x is f(x)=15
Andreyy89

Answer:

  {2, 8}

Step-by-step explanation:

We want to find x for ...

  15 = 4|x -5| +3

  12 = 4|x -5| . . . . subtract 3

  3 = |x -5| . . . . . . divide by 4

  ±3 = x -5 . . . . . . show the meaning of absolute value

  5 ±3 = x = {2, 8} . . . . . add 5

The values of x for which f(x) = 15 are 2 and 8.

3 0
3 years ago
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