Answer:
Step-by-step explanation:
4*3^x+1=27+(3^2)^x
(3^2)^x=(3^x)^2
3^x=t
4t+1=27+t^2
t^2-4t+27-1=0
t^2-4t+26=0
delta=4^2-4*1*26=16-84=-68<0
the equation has not real solutions
Answer:
p < -7
Step-by-step explanation:
.................
36; 351; 66; 1,017; 113,331; 1,968; 537; 417; 3,813
Answer:
ANSWER B
Step-by-step explanation:
d=(120-4t)
30=120-4t
4t=120-30=90
t=90/4=22.5 s
-30==120-4t
4t=120+30=150
t=150/4=37.5 s
The answer you are looking for would be 2.
This can be found by solving with PEMDAS. First, you do the 4^2 (4*4), which equals 16. Next, you multiply 16 by 7, to get 112. Then, you'd divide 112 by 8. This gives you 14. Finally, subtract 12 from 14 to get your final answer of 2.
I hope this helps!
