Please help math question 1,2,3,4,5
1 answer:
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Inverses
solve for x
replace x with f inverse
replace y with x
so
first minus 2 both sides
y-2=√(2x-3)
square both sides
y^2-4y+4=2x-3
add 3 to both sides
y^2-4y+7=2x
divide both sides y 2
(y^2-4y+7)/2=x
x turns to f inverse and y turns to x
f(x)⁻¹=
looks like they didn't want to expand the binomial
y=
answer si A
solve for x
replace x with f inverse
replace y with x
so
first minus 2 both sides
y-2=√(2x-3)
square both sides
y^2-4y+4=2x-3
add 3 to both sides
y^2-4y+7=2x
divide both sides y 2
(y^2-4y+7)/2=x
x turns to f inverse and y turns to x
f(x)⁻¹=
looks like they didn't want to expand the binomial
y=
answer si A
Answer:
see attached
Step-by-step explanation:
The line at the lower left of the shaded region is x+y=12. The shaded area is above that line because is represents a minimum amount of exercise.
