Answer:5
Step-by-step explanation:
Apply the rule: 
![3[2 ln(x-1) - lnx] + ln(x+1)=3[ln(x-1)^{2} - lnx ] + ln(x+1)](https://tex.z-dn.net/?f=3%5B2%20ln%28x-1%29%20-%20lnx%5D%20%2B%20ln%28x%2B1%29%3D3%5Bln%28x-1%29%5E%7B2%7D%20-%20lnx%20%5D%20%2B%20ln%28x%2B1%29)
Apply the rule : 
![3[2 ln(x-1) - lnx] + ln(x+1)=3ln\frac{(x-1)^{2} }{x} + ln(x+1)](https://tex.z-dn.net/?f=3%5B2%20ln%28x-1%29%20-%20lnx%5D%20%2B%20ln%28x%2B1%29%3D3ln%5Cfrac%7B%28x-1%29%5E%7B2%7D%20%7D%7Bx%7D%20%2B%20ln%28x%2B1%29)
Apply the rule: 
![3[ln (x-1)^{2} -ln x]+ln (x+1)= ln \frac{(x-1)^{6} }{x^{3} } +log(x+1)](https://tex.z-dn.net/?f=3%5Bln%20%28x-1%29%5E%7B2%7D%20-ln%20x%5D%2Bln%20%28x%2B1%29%3D%20ln%20%5Cfrac%7B%28x-1%29%5E%7B6%7D%20%7D%7Bx%5E%7B3%7D%20%7D%20%2Blog%28x%2B1%29)
Finally, apply the rule: log a + log b = log ab
![3[ln(x-1)^{2} -ln x]+log(x+1)=ln\frac{(x-1)^{6}(x+1) }{x^{3} }](https://tex.z-dn.net/?f=3%5Bln%28x-1%29%5E%7B2%7D%20-ln%20x%5D%2Blog%28x%2B1%29%3Dln%5Cfrac%7B%28x-1%29%5E%7B6%7D%28x%2B1%29%20%7D%7Bx%5E%7B3%7D%20%7D)
Hey I'm in flvs too but I have a different teacher, what class and module is your DBA for?
Answer:
16 meters.
Step-by-step explanation:
There are two things to keep in mind at this point, the first is that a square has all its sides equal and the second is that the perimeter in this type of figure is the sum of all the sides.
Knowing the above, we can deduce that therefore each side of the square measures 4 meters and the perimeter could be calculated since we know the value of all the sides, we know that a square has four sides:
p = 4 +4 +4 +4
p = 16
that is to say that the perimeter is equal to 16 meters.
Answer:
2.5
Step-by-step explanation:
Simplifying
2y + -1.7 = 3.3
Reorder the terms:
-1.7 + 2y = 3.3
Solving
-1.7 + 2y = 3.3
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '1.7' to each side of the equation.
-1.7 + 1.7 + 2y = 3.3 + 1.7
Combine like terms: -1.7 + 1.7 = 0.0
0.0 + 2y = 3.3 + 1.7
2y = 3.3 + 1.7
Combine like terms: 3.3 + 1.7 = 5
2y = 5
Divide each side by '2'.
y = 2.5
Simplifying
y = 2.5