The points A,B,C,D make up the circumference of the circle
The measure of angle BAD is 65 degrees
<h3>How to determine the measure of angle BAD?</h3>
The measure of angle ODB is given as:
ODB = 25 degrees
Considering the triangle BOD, we have:
ODB + BOD + DBO = 180
Where:
ODB = DBO = 25
So, we have:
25 + BOD + 25 = 180
Solve for BOD
BOD = 130 degrees
The angle at an arc is twice the angle at the circumference.
So, we have:
BOD = 2 * BAD
Substitute 130 for BOD
130 = 2 * BAD
Divide both sides by 2
65 = BAD
Hence, the measure of angle BAD is 65 degrees
Read more about angle measures at:
brainly.com/question/17972372
Y- intercept is a point where any graph crosses the y- axis.
X- intercept is a point where any graph crosses the x- axis.
This means the coordinate of the point of intersection will always have the x point as 0. So any point of the form ( 0, y) is the y- intercept. Any point of the form (x,0) is the x- intercept.
Given point are :
(0,-6) : y intercept
(-2,0) : x intercept
(-6,0): x- intercept
(0,-2): y- intercept
Answer:
They provide a general summary of the status of all your Outbound, Inbound, Third Party and Import shipments. They allow you to classify and reorder the data in the table. Allow you to use filters to reduce the amount of shipment information displayed in the view
Answer:
17/42
Step-by-step explanation:
Just checked
is a complex number that satisfies
![\begin{cases}r\cos x=-3\\[1ex]r\sin x=4\\[1ex]r=\sqrt{(-3)^2+4^2}\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7Dr%5Ccos%20x%3D-3%5C%5C%5B1ex%5Dr%5Csin%20x%3D4%5C%5C%5B1ex%5Dr%3D%5Csqrt%7B%28-3%29%5E2%2B4%5E2%7D%5Cend%7Bcases%7D)
The last equation immediately tells you that
.
So you have
![\begin{cases}\cos x=-\dfrac35\\[1ex]\sin x=\dfrac45\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%5Ccos%20x%3D-%5Cdfrac35%5C%5C%5B1ex%5D%5Csin%20x%3D%5Cdfrac45%5Cend%7Bcases%7D)
Dividing the second equation by the first, you end up with
Because the argument's cosine is negative and its sine is positive, you know that
. This is important to know because it's only the case that
whenever
. The inverse doesn't exist otherwise.
However, you can restrict the domain of the tangent function so that an inverse can be defined. By shifting the argument of tangent by
, we have
All this to say
So,
.
