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san4es73 [151]
3 years ago
15

Pleasee help mee i begg

Mathematics
1 answer:
Licemer1 [7]3 years ago
8 0

Answer:

Step-by-step explanation:

3:9 = 1:3

1:7 = 2:14

12:4 = 24:8

20:5 = 40:10

Hope it helps!

You might be interested in
Find the value of y if the measure of the vertex angle is 64 degrees and base angle is (2y -11)
Dafna1 [17]

Answer: 35


180 = 64 + y + 2y - 11

105 = 3y

y = 35




5 0
3 years ago
7x + 2 = -19 (b) 3x - 1/3 = 5 (c) 5x - 4 = 21 (d) -7x = 21 (e) 18 - 7x = -3 (f) 3(x + 4) = 21 (g) 3x - 9 = 5x - 3 (h) 4x + 6 - 7
Hunter-Best [27]

Answer:

Step-by-step explanation:

a)7x + 2 = -19  {subtract 2 from both sides}

7x + 2 -  2 = -19 - 2

            7x = -21   {Divide both sides by 7}

         7x/7 = -21/7

             x = -3

b) 3x - 1/3 = 5

3x - 1/3 +1/3 = 5 + 1/3  {Add 1/3 to both sides}

               3x =15/3 + 1/3

               3x =16/3

             3x/3 = 16/3*3 {Divide both sides by 3}

                 x =16/9

                 x =1 7/9

c) 5x - 4  = 21

5x -4 + 4 = 21 +4 {Add 4 to both sides}

          5x = 25

       5x/5 = 25/5    {Divide both sides by 5}

            x = 5

d) -7x  = 21 {Divide both sides by -7}

-7x/-7 = 21/-7

        x = -3

e)   18 - 7x = -3

18 - 7x - 18 = -3 - 18   {Subtract 18 from both sides}

          -7x = -21   {Divide both sides by -7}

      -7x/-7 = -21/-7

              x = 3

f)     3(x+4) = 21   {use distributive property}

   3x + 3*4 = 21

    3x  + 12 = 21

3x + 12 - 12 = 21 - 12       {Subtract 12 from both sides}

              3x = 9   {Divide both sides by 3}

           3x/3 = 9/3

                 x = 3

g)     3x - 9 = 5x - 3  {add 9 to both sides}

 3x - 9 + 9 = 5x - 3 + 9

             3x = 5x + 6

       3x - 5x = 5x + 6 - 5x     { subtract 5x form both sides}

             -2x = 6  {Divide both sides by -2}

         -2x/-2 = 6/-2

                 x = -3

h) 4x + 6 - 7x + 9 = 18   {Add the like terms}

           -3x  + 15 = 18  {Subtract 15 from both sides}

      -3x + 15 -15 = 18 - 15

                    -3x = 3   {Divide both sides by -3}

               -3x/-3 = 3/-3

                      x = -1

i) \frac{-4}{9}x = -36

Multiply both sides by 9

9*\frac{-4}{9}x =9*-36

 -4x = -324     {Divide both sides by -4}

-4x/-4 = -324/-4

       x = -81

j)\frac{-7}{8}x - 6 = 8   {Add 6 to both sides}

\frac{-7}{8}x-6+6=8+6\\\\\frac{-7}{8}x=14\\    {Multiply both sides by 8}

\frac{-7}{8}x*8=14*8\\\\-7x=14*8\\       {Divide both sides by -7}

\frac{-7}{-7}x=\frac{14*8}{-7}

x =-2*8

x = -16

8 0
3 years ago
Derivative of <br> <img src="https://tex.z-dn.net/?f=x%5E%7B3%7D" id="TexFormula1" title="x^{3}" alt="x^{3}" align="absmiddle" c
ch4aika [34]

f(x)=x^3e^{2x}\\\\f'(x)=(x^3e^{2x})'\qquad\text{use}\ (f\cdot g)'(x)=f'(x)g(x)+f(x)g'(x)\\\\=(x^3)'(e^{2x})+(x^3)(e^{2x})'\\\\\text{use}\ (x^n)'=nx^{n-1}\ \text{and}\ (e^x)'=e^x\ \text{and}\ f'[g(x)]=f'(g(x))\cdot g'(x)\\\\=3x^2e^{2x}+x^3e^{2x}\cdot2\\\\=\boxed{3x^2e^{2x}+2x^3e^{2x}}

5 0
3 years ago
Write the quadratic equation whose roots are 3 and 1, and whose leading coefficient is 1
Serhud [2]

Answer:

x² - 4x + 3 = 0

Step-by-step explanation:

given roots x = a and x = b then the corresponding factors are

(x - a) and (x - b)

the equation is then the product of these factors , that is

(x - a)(x - b) = 0

given

roots x = 3 and x = 1 , then factors are (x - 3) and (x - 1) , then

(x - 3)(x - 1) = 0 ← expand factors using FOIL

x² - 4x + 3 = 0

6 0
2 years ago
Helppp ..
leva [86]

Answer:

h(x) =  3(x - 5)^2 + 6.

Step-by-step explanation:

g(x) = 3x^2 + 8

Shifting 5 units to the right gives:

3(x - 5)^2 + 8

Now 2 units down :

3(x - 5)^2 + 8 - 2

= 3(x - 5)^2 + 6.

5 0
2 years ago
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