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3 years ago

11

X+y=3 3x-y=-7 elimination method

1 answer:

Alina [70]3 years ago

3 0

x + y = 3

+ x - y = -7

-------------------

2x = -4

x = -2

-2 + y = 3

y = 5

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Clarice Sloan is a shift supervisor for Ace

Igoryamba

The net pay is the amount left after taxes and deductions have been removed from the gross pay.

Her monthly gross pay is: $4111.93

The deductions are:

$\mathbf{FIT = \$102}$

$\mathbf{SIT = 3.2\%}$

$\mathbf{CIT = 1.8\%}$

Let her gross pay be x.

So, we have:

$\mathbf{Net = x - FIT - x \times SIT - x \times CIT}$

So, we have:

$\mathbf{3804.33 = x - 102 - x \times 3.2\%- x \times 1.8\%}$

Express percentage as decimals

$\mathbf{3804.33 = x - 102 - x \times 0.032- x \times 0.018}$

$\mathbf{3804.33 = x - 102 - 0.032x - 0.018x}$

Add 102 to both sides

$\mathbf{3906.33 = x - 0.032x - 0.018x}$

$\mathbf{3906.33 = 0.95x}$

Divide both sides by 0.95

$\mathbf{4111.93 = x}$

Rewrite as:

$\mathbf{x = 4111.93 }$

Hence, her monthly gross pay is: $4111.93

Read more about gross and net pay at:

brainly.com/question/8952173

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2 years ago

Please help! I'll give out the brainiest!

Burka [1]

A) Puppies to Kittens.

This is because if you divide 15 and 12 by the lowest, you get 5:2 (=:

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2 years ago

- What is the value of the expression 3m(2m) when m = 4?

andrew11 [14]

Answer:96

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2 years ago

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GrogVix [38]

Given:

$m \angle A B D=96^{\circ}$

$m \angle 2 =m \angle 1+ 26^{\circ}$

To find:

$m \angle 1$

Solution:

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$m \angle 1+ m \angle 2 = m \angle ABD$

Substitute $m \angle 2 =m \angle 1+ 26^{\circ}$ .

$m \angle 1+ m \angle 1 + 26^\circ = 96^\circ$

$2m \angle 1+ 26^\circ = 96^\circ$

Subtract 26° from both sides.

$2m \angle 1+ 26^\circ -26^\circ = 96^\circ -26^\circ$

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Divide by 2 on both sides, we get

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3 years ago

Read 2 more answers

Please Help me!!!

drek231 [11]

Step-by-step explanation:

The displacement of a particle d (in km) as a function of time t (in hours) is given by :

$d=2t^3+5t^2-3$

Displacement at t = 4 hours,

$d(4)=2(4)^3+5(4)^2-3=205\ km$

Velocity of particle is given by :

$v=\dfrac{dd}{dt}\\\\v=\dfrac{d(2t^3+5t^2-3)}{dt}\\\\v=6t^2+10t$

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Acceleration of the particle is given by :

$a=\dfrac{dv}{dt}\\\\a=\dfrac{d(6t^2+10t)}{dt}\\\\a=12t+10$

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Therefore, the displacement, velocity and acceleration at t = 4 hours is 205 km, 136 km/h and 58 km/h² respectively.

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2 years ago