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hoa [83]
3 years ago
14

Help please? 26x-2(3x+4y)-10y

Mathematics
1 answer:
AlladinOne [14]3 years ago
6 0

Answer:

20x-18y

Step-by-step explanation:

26x-2(3x+4y)-10y

26x-6x-8y-10y

20x-18y go doawnload the app photomath its a great tool

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ASAP NO WORK JUST ANSWER
Hunter-Best [27]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
Use the diagram to find the height of statue.round to the nearest tenth
jeyben [28]

Answer:

7.3 ft

Step-by-step explanation:

The information given represents a right angle triangle with the following:

reference angle = 52°

Adjacent side length = 5.7 ft.

Opposite side length = height of the statue = h

Applying the trigonometric ratio formula, we would have:

tan(52) = \frac{h}{5.7}

Multiply both sides by 5.7

tan(52) \times 5.7 = \frac{h}{5.7} \times 5.7

tan(52) \times 5.7 = h

h = 7.3 ft (nearest tenth)

6 0
3 years ago
Which of the following ordered pairs are a solution for the equation y = 6x − 3?
storchak [24]

Answer:

-1,9

Step-by-step explanation:

I got them wrong so it showed me the right answer

5 0
3 years ago
Solve the equation below for x. 5x- 2 = -7 What is x=_____
Sati [7]

Answer:

x = -1

Step-by-step explanation:

Start with adding 2 to -7

-7 + 2

=-5

Then divide by 5

-5/5

=-1

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=5x%5E%7B2%7D%20%2B11x%2B2%3D0" id="TexFormula1" title="5x^{2} +11x+2=0" alt="5x^{2} +11x+2=0"
eimsori [14]

The solutions to the quadratic equation in the exact form are x = -1/2 or x = -5

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the solution to the quadratic equation?</h3>

A quadratic equations can be split to several equations and it can be solved as a whole

In this case, the quadratic equation is given as

5x^2 + 11x + 2 = 0

Using the form of the quadratic equation y = ax^2 + bx + c, we have

a = 5, b = 11 and c = 2

The quadratic equation can be solved using the following formula

x = (-b ± √(b^2 - 4ac))/2a

Substitute the known values of a, b and c in the above equation

x = (-11 ± √(11^2 - 4 * 5 * 2))/2*2

Evaluate the exponent

x = (-11 ± √(121 - 4 * 5 * 2))/2*2

Evaluate the products

x = (-11 ± √(121 - 40))/4

Evaluate the sum

x = (-11 ± √(81))/4

Take the square root of 81

x = (-11 ± 9)/4

Expand

x = 1/4 * (-11 + 9) or x = 1/4 * (-11 - 9)

Evaluate the difference

x = 1/4 * -2 or x = 1/4 * -20

Evaluate the product

x = -1/2 or x = -5

Hence, the solutions to the quadratic equation in the exact form are x = -1/2 or x = -5

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

4 0
2 years ago
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