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hoa [83]
3 years ago
14

Help please? 26x-2(3x+4y)-10y

Mathematics
1 answer:
AlladinOne [14]3 years ago
6 0

Answer:

20x-18y

Step-by-step explanation:

26x-2(3x+4y)-10y

26x-6x-8y-10y

20x-18y go doawnload the app photomath its a great tool

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The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. Find the probability
yawa3891 [41]

<u>Complete Question</u>

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Find the probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

Answer:

0.9875

Step-by-step explanation:

Total Number of Guests which forms the Sample Space, n(S)=80

Let the Event (a friend of the bride) =A

Let the Event (a friend of the groom) =B

n(A) =59

n(B)=50

Friends of both bride and groom, n(A \cap B)=30

Therefore:

n(A \cup B)=n(A)+n(B)-n(A \cap B)\\n(A \cup B)=59+50-30\\n(A \cup B)=79

The number of Guests who was a friend of the bride OR of the groom = 79

Therefore:

The probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

P(A \cup B) =\dfrac{n(A \cup B) }{n(S)} \\\\=\dfrac{79 }{80}\\\\=0.9875

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3 years ago
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