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Volgvan
3 years ago
8

Помогите пожалуйста срочно надо пожалкйста

Mathematics
1 answer:
romanna [79]3 years ago
7 0

Answer:

Me??? :(

Step-by-step explanation:

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What is the math function of 3x,=y
vichka [17]
Direct variation. Have a nice day!
4 0
3 years ago
1.) What is the slope of the line perpendicular to a line with the slope of<br> 2/3?
daser333 [38]

Answer:

-3/2

Explanation:

Slopes of perpendicular lines are opposite reciprocals, which means you flip them and switch them from positive to negative, or the other way around.

8 0
3 years ago
In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta
Advocard [28]

Answer:

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.3246

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.3646\frac{0.06}{\sqrt{8}} = 0.0502

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

8 0
3 years ago
In 2011, a U.S. Census report determined that 71% of college students work. A researcher thinks this percentage has changed sinc
coldgirl [10]

Answer:

Note: The full question is attached as picture below

a) Hо : p = 0.71

Ha : p ≠ 0.71

<em>p </em>= x / n

<em>p </em>= 91/110

<em>p </em>= 0.83.

1 - Pо = 1 - 0.71 = 0.29.

b) Test statistic = z

= <em>p </em>- Pо / [√Pо * (1 - Pо ) / n]

= 0.83 - 0.71 / [√(0.71 * 0.29) / 110]

= 0.12 / 0.043265

= 2.77360453

Test statistic = 2.77

c) P-value

P(z > 2.77) = 2 * [1 - P(z < 2.77)] = 2 * 0.0028

P-value = 0.0056

∝ = 0.01

P-value < ∝

Reject the null hypothesis.  There is sufficient evidence to support the researchers claim at the 1% significance level.

6 0
3 years ago
(2,7) (-1-8) write the equations in slope intercept form
AveGali [126]

Answer:

y-mx+b

(2,7) (-1, -8)

y=5x-3

8 0
3 years ago
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