Question

2. You throw a softball straight up into the air at a velocity of 30 feet per second. You release the softball at a height of 5.8 feet and catch it when it falls back to a height of 6.2 feet. Use the position equation to write a mathematical model for the height of the softball

Answer 1

Answer:

$-16t^2+30t+5.8$

Step-by-step explanation:

We are given that

Initial velocity=30 ft/s

Initial position=$s_0=5.8 ft$

We have to write a mathematical model for height of the softball by using the position equation

The position equation on Earth's surface is given by

$h(t)=-16t^2+v_0t+s_0$

Where $v_0=$ Initial velocity

$s_0$=Initial position

Substitute the values in the equation then, we get

$h(t)=-16t^2+30t+5.8$

Hence, the mathematical model for height of the softball is given by

$-16t^2+30t+5.8$