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Alborosie
3 years ago
10

Is an Obtuse triangle a Acute triangle? Yes or no? And why or why not?

Mathematics
1 answer:
777dan777 [17]3 years ago
5 0

Answer:

No, this is because the word obtuse is in the name obtuse triangle as well as it being a whole different angle than an acute angle. Obtuse angles are are greater than 90 degress but less than 180 while the acute angle is less than 90.

Step-by-step explanation:

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KengaRu [80]
Hi.

22-5(2x+4) \\ \\ \implies 22-10x-20 \\ \\ \implies -10x+22-20 \\ \\ \implies -10x +2

Hence,

The correct option is \boxed{\sf b. -10x+2}

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7 0
3 years ago
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If Cyrus knows that △ABC∼△EDC and AB¯¯¯¯¯¯¯¯∥ED¯¯¯¯¯¯¯¯, how can he prove that line m passing through AB¯¯¯¯¯¯¯¯ has the same sl
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4 0
1 year ago
I need to find the surface area and volume of all three figures. If you could provide what equations you used to I will be grate
Margarita [4]

Answer:

Part 1) <em>Sphere</em> The surface area is equal to SA=196\pi\ m^{2} and the volume is equal to V=\frac{1,372}{3}\pi\ m^{3}

Part 2) <em>Cone</em> The surface area is equal to SA=(16+4\sqrt{65})\pi\ units^{2} and the volume is equal to V=\frac{112}{3}\pi\ units^{3}

Part 3) <em>Triangular Prism</em> The surface area is equal to SA=51.57\ mm^{2} and the volume is equal to V=17.388\ mm^{3}

Step-by-step explanation:

Part 1) The figure is a sphere

a) Find the surface area

The surface area of the sphere is equal to

SA=4\pi r^{2}

we have

r=14/2=7\ m ----> the radius is half the diameter

substitute

SA=4\pi (7)^{2}

SA=196\pi\ m^{2}

b) Find the volume

The volume of the sphere is equal to

V=\frac{4}{3}\pi r^{3}

we have

r=14/2=7\ m ----> the radius is half the diameter

substitute

V=\frac{4}{3}\pi (7)^{3}

V=\frac{1,372}{3}\pi\ m^{3}

Part 2) The figure is a cone

a) Find the surface area

The surface area of a cone is equal to

SA=\pi r^{2} +\pi rl

we have

r=4\ units

h=7\ units

Applying Pythagoras Theorem find the value of l (slant height)

l^{2}=r^{2} +h^{2}

substitute the values

l^{2}=4^{2} +7^{2}

l^{2}=65

l=\sqrt{65}\ units

so

SA=\pi (4)^{2} +\pi (4)(\sqrt{65})

SA=16\pi +4\sqrt{65}\pi

SA=(16+4\sqrt{65})\pi\ units^{2}

b) Find the volume

The volume of a cone is equal to

V=\frac{1}{3}\pi r^{2}h

we have

r=4\ units

h=7\ units

substitute

V=\frac{1}{3}\pi (4)^{2}(7)

V=\frac{112}{3}\pi\ units^{3}

Part 3) The figure is a triangular prism

a) The surface area of the triangular prism is equal to

SA=2B+PL

where

B is the area of the triangular base

P is the perimeter of the triangular base

L is the length of the prism

<em>Find the area of the base B</em>

B=\frac{1}{2} (2.7)(2.3)=3.105\ mm^{2}

<em>Find the perimeter of the base P</em>

P=2.7*3=8.1\ mm

we have

L=5.6\ mm

substitute the values

SA=2(3.105)+(8.1)(5.6)=51.57\ mm^{2}

b) Find the volume

The volume of the triangular prism is equal to

V=BL

where

B is the area of the triangular base

L is the length of the prism

we have

B=3.105\ mm^{2}

L=5.6\ mm

substitute

V=(3.105)(5.6)=17.388\ mm^{3}

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3 years ago
Convert 10010001 from binary to hexadecimal.
USPshnik [31]
10010001 is 91 in hexadecimal
6 0
2 years ago
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I'm not doing so well soo pls answer fast..
Marta_Voda [28]

Answer:

The answer is B

Step-by-step explanation:

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