Answer:
The gallons of fuel car need to travel 30 km is <u>0.75</u> approximately .
Step-by-step explanation:
Given:
The car can travel 25 miles per gallon. (1 mile = 1.6 km)
Now, we need to convert 25 miles into km .
25 miles = 25 × 1.6 km
= 40 km
So, the car can travel 40 km per gallon.
Then, we find out in 1 km how many gallons are used:
Now, we find out how much gallons of fuel will the car need to travel 30 km:
Gallons of fuel the car need to travel 30 km = 
= 
.
Therefore, the gallons of fuel car need to travel 30 km is 0.75 approximately.
MLJ is congruent to POL( corresponding angles)
POL= 59
I don't know what the "six-step method" is supposed to be, so I'll just demonstrate the typical method for this problem.
Let <em>x</em> be the amount (in gal) of the 50% antifreeze solution that is required. The new solution will then have a total volume of (<em>x</em> + 60) gal.
Each gal of the 50% solution used contributes 0.5 gal of antifreeze. Similarly, each gal of the 30% solution contributes 0.3 gal of antifreeze. So the new solution will contain (0.5 <em>x</em> + 0.3 * 60) gal = (0.5 <em>x</em> + 18) gal of antifreeze.
We want the concentration of antifreeze to be 40% in the new solution, so we need to have
(0.5 <em>x</em> + 18) / (<em>x</em> + 60) = 0.4
Solve for <em>x</em> :
0.5 <em>x</em> + 18 = 0.4 (<em>x</em> + 60)
0.5 <em>x</em> + 18 = 0.4 <em>x</em> + 24
0.5 <em>x</em> - 0.4 <em>x</em> = 24 - 18
0.1 <em>x</em> = 6
<em>x</em> = 6/0.1 = 60 gal
