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3 years ago

5

Kevin wants to purchase a new car that costs $10,000. Every week he saves up $250. It has been 30 weeks. How much money does he

have? Does he have enough money to buy the car?

1 answer:

meriva3 years ago

6 0

Kevin has $7,500 after 30 weeks. He does not have enough money for the car.

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Can you choose any two distinct points on a line to calculate the slope? True or False?

marin [14]

True, u can choose any two distinct points on a line to calculate the slope

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3 years ago

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i live in a house that 3 metets below sea level go to school 5 meters above sea level how many meters do i go

RideAnS [48]

3 meters below sea level represents a -3
From -3 to 0 is 3
3 + 5 above sea level = 8 meters
There are 8 meters between the house and the school

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3 years ago

Haruka hiked several kilometers in the morning. She only hiked 6 kilometers in the afternoon, which was 25% less she had hiked i

SOVA2 [1]

WEW can use a simple equation to solve this

Let x be the number of kilometers she hiked in the morning . Then

x - 0.25x = 6 (Note 0.25 = 25 %)

0.75x = 6

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3 years ago

Check my answer please!

Ray Of Light [21]

The answer is C, 4.

you combine like terms and that is the answer you get.

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3 years ago

Abigail and Spencer calculate the slope of the line between the points (3,-1) and (5,4) in different ways. Abigail calculates th

telo118 [61]

Answer:

Spencer and Abigail are correct

Lauren is incorrect

Step-by-step explanation:

Spencer and Abigail are correct

Slope = change in y ÷ change in x

Or $m=\dfrac{y_2-y_1}{x_2-x_1}$

Let $(x_1,y_1)$ = (3, -1)

Let $(x_2,y_2)$ = (5, 4)

$\implies m=\dfrac{4-(-1)}{5-3}=\dfrac52$

This is Spencer's method

Let $(x_1,y_1)$ = (5, 4)

Let $(x_2,y_2)$ = (3, -1)

$\implies m=\dfrac{-1-4}{3-5}=\dfrac52$

This is Abigail's method

It doesn't matter which point you label as point 1 and point 2, as long as you carry out the slope calculation correctly.

Lauren's calculation is wrong as she calculated her slope as:

$m=\dfrac{y_2-y_1}{x_1-x_2}$

where it should have been $m=\dfrac{y_2-y_1}{x_2-x_1}$

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2 years ago