<u>Q</u><u>uest</u><u>ion</u><u>:</u>
To Simplify:
118 {121÷(11×11)-(-4)-(3-7)}
<u>Solu</u><u>tion</u>:
↠118 {121÷121+4-(-4)}
↠118 {1+4+4}
↠118 {5+4}
↠118{9}
↠118×9
↠1062
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The upper Solution is done by applying BODMAS
<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>
B→ Bracket
O→ Of
D→ Division
M→ Multiplication
A→ Addition
S→ Subtraction
Answer:
See explanation below
Step-by-step explanation:
The best explanation is noticing that in order to get from the point R (12, 1) to the point Q (7, 4) we move 5 units to the left and 3 units up. And to go from point Q (7, 4) to point P (2, 7) we do exactly the same: move 5 units to the left and 3 units up. That means that these points are all connected via the same rate of change: - 3/5, which is in fact the slope of the line the three points belong to.
21 + 28 = 49 students
Ration of history 21 to students 49 = d)21:49
Average rate of change is (f(8) - f(-6))/(8 - (-6)) = ((<span>|8 + 3| -1) - (</span><span>|-6 + 3| -1))/(8 + 6) = ((</span><span>|11| -1) - (</span><span>|-3| -1))/14 = ((11 - 1) - (3 - 1))/14 = (10 - 2)/14 = 8/14 = 4/7</span>
