Answer:
38.32 mL is minimal volume of hot water that is needed to dissolve 2.1 g of pure acetanilide.
Explanation:
Mass of acetanilide to be dissolved in hot water = 2.1 g
Mass of hot water to be used = m
Solubility of acetanilide = 55 g/L
This means that 55 grams of acetanilide dissolves in 1 L of hot water.
Then 1 grams of acetanilide will dissolve in :

0.0382 L = 0.0382 × 1000 mL =38.2 mL
1 L = 1000 mL
38.32 mL is minimal volume of hot water that is needed to dissolve 2.1 g of pure acetanilide.
Okay
Mr (H2O)= 18g
therefore moles of H2O
is 720.8/18= 40.04mol
the ratio of H2 to O2 to H2O is
2 : 1 : 2
so moles of H2 is same as H2O here
H2= 40.04moles
moles of O2 is half
so 40.04 x 0.5
20.02moles
grams of O2 is
its moles into Mr of O2
that's 20.02 x 32 = 640.64g
1) Increasing the temperature.
2) Increasing the concentration (in solution).
3) Increasing the pressure (in gases).
4) Increasing the surface area of a solid.
The shape of an ammonia molecule is trigonal pyramidal (see the image below).
The N atom is at the top of the pyramid and the three H atoms are at the corners of a triangular base.