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Dmitry_Shevchenko [17]
3 years ago
7

Unit 5 part 2. K12. Who killed were and how.

Mathematics
1 answer:
Daniel [21]3 years ago
6 0

Answer:

Step-by-step explanation:

Charlemagne son died in Aisa he was shot

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What is the approximate side length of a square game board with and area of 188 in. squared.
anastassius [24]

Answer:

Side length of a square game board is  

11.916

inches.

Explanation:

If the area is  

142

 

∈

2

, as area is square of side length of a square,

Side length is  

√

142

=

11.916

inches.

Step-by-step explanation:

6 0
2 years ago
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What Is The radius? (Round to the nearest tenth)
mr_godi [17]
The radius can be found with the Pythagorean theorem. Assuming r is the radius, 14²+r²=17². Multiply it out to 196+r²=289. Subtract 196 from both sides and you're left with r²=93. So, r=√93, or about 9.6 to the nearest tenth.
8 0
3 years ago
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Write an equation that represents the line. (-3,-6) and (2,-2) use exact numbers
Ilia_Sergeevich [38]

Given:

The line passes through (-3,-6) and (2,-2).

To find:

The equation of line.

Solution:

If a line passes through two points (x_1,y_1)\text{ and }(x_2,y_2), then the equation of line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

The line passes through (-3,-6) and (2,-2). So, the equation of line is

y-(-6)=\dfrac{-2-(-6)}{2-(-3)}(x-(-3))

y+6=\dfrac{-2+6}{2+3}(x+3)

y+6=\dfrac{4}{5}(x+3)

y+6=\dfrac{4}{5}(x)+\dfrac{4}{5}(3)

Subtract 6 from both sides.

y=\dfrac{4}{5}(x)+\dfrac{12}{5}-6

y=\dfrac{4}{5}(x)+\dfrac{12-30}{5}

y=\dfrac{4}{5}(x)+\dfrac{-18}{5}

y=\dfrac{4}{5}(x)-\dfrac{18}{5}

Therefore, the equation of line is y=\dfrac{4}{5}(x)-\dfrac{18}{5}.

3 0
3 years ago
Please solve the problem with steps
Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}

The first one: (\frac{1}{2})^{n-1} is a geometric sequence of first term (a_1) "1" and common ratio (r) " \frac{1}{2} ", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{2} } =\frac{1}{\frac{1}{2} } =2

The second one: \frac{1}{6^{n-1}} is a geometric sequence of first term "1", and common ratio (r) " \frac{1}{6} ". Again, since the common ratio is smaller than one, we can find its infinite sum:

Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{6} } =\frac{1}{\frac{5}{6} } =\frac{6}{5}

now we simply combine the results making sure we do the indicated difference: Infinite total sum= 2-\frac{6}{5} =\frac{10-6}{5} =\frac{4}{5}

8 0
3 years ago
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Northside High School is having a spaghetti dinner fundraiser. In order to advertise, students place flyers on neighborhood door
-BARSIC- [3]

2 hours = 60*2 = 120 minutes

120/120 = 1

Margie handed out 1 flyer every minute

Jaxon handed 18/15 = 1.2 flyers per minute

 so Jaxon is faster

4 0
3 years ago
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