Answer:
the integer in question lies between 13 and 14.
Step-by-step explanation:
Review the perfect squares in the neighborhood of 194. The first that came to my mind was 225 (the squre of 15), and then 196 (the square of 14), and then 169, the square of 13.
Since 169 < x^2 < 196, the integer in question lies between 13 and 14.
Check with a calculator: √194 ≈ 13.93
D 30 degrees that's the answer.
Take the derivative with respect to t
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
divide by w
we add sin(wt) to both sides
divide both sides by cos(wt)
OR
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be
since 2npi is just the period of cos
substituting our second soultion we get
since 2npi is the period
so the maximum value =
minimum value =
Hi,
The answer you are looking for is 2. (-4,2)
Have a great day & remember to mark brainliest if I helped :)
Answer:
w=4
Step-by-step explanation:
2(48)+2(8w)+2(6w)=208
1) Start by Distributing the value outside of the parenthesis:
96+16w+12w=208
2) Combine alike terms:
96+28w=208
3) Subtract 96 from both sides:
28w=112
4)Divide both sides by 28 to isolate w:
w=4
Let me know if you do not understand :)