Basically the remainder theorem links the remainder of division by a binomial with the value of a function at a point while the factor theorem links the factors of polynomial to its zeros
Under a counterclockwise rotation about the origin of 90°
a point (x , y ) → (- y, x ), hence
A(2, 1 ) → A'(- 1, 2 )
Answer:
(a) 0.4242
(b) 0.0707
Step-by-step explanation:
The total number of ways of selecting 8 herbs from 12 is

(a) If 2 herbs are selected, then there are 8 - 2 = 6 herbs to be selected from 12 - 8 = 10. The number of ways of the selection is then

Note that this is the number of ways that both are included. We would have multiplied by 2! if any of them were to be included.
The probability = 
(b) If 5 herbs are selected, then there are 8 - 5 = 3 herbs to be selected from 12 - 5 = 7. The number of ways of the selection is then

This is the number of ways that both are included. We would have multiplied by 5! if any of them were to be included. In that case, our probability will exceed 1; this implies that certainly, at least, one of them is included.
The probability = 
Answer:
hello! although i am not really knowlegeble about this subject, i hope the lengths below can help you solve the problem :)
Step-by-step explanation:
side length: 62.03inches
perimeter: 168.06
area:1276
if this does help you, a brainliest would be appreciated!
Answer:
Therefore the value of x is

Step-by-step explanation:
Given:
which is

To Find:
x = ? using Quadratic Formula
Solution:
For a Quadratic Equation ax² + bx + c = 0 , Formula Method is given as

On Comparing with above we get

Substituting a , b , c in Formula method we get

Therefore the value of x is
