Answer:
The function has at least 1 zero within the interval [-2,5].
Step-by-step explanation:
The intermediate value theorem states that, for a function continuous in a certain interval ![[a,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D)
, then the function takes any value between 
and 
at some point within that interval.
This theorem has an important consequence:
If a function 
is continuous in an interval [a,b], and the sign of the function changes at the extreme points of the interval:
(or viceversa)
Then the function f(x) has at least one zero within the interval [a,b].
We can apply the theorem to this case. In fact, here we have a function f(x) continuous within the interval
[-2,5]
And we also know that the function changes sign at the extreme points of the interval:
Therefore, the function has at least 1 zero within the interval [-2,5], so there is at least one point x' within this interval such that
Answer:
-45, -44, -43
Step-by-step explanation:
Let the smallest consecutive integer be x. Consecutive integers have a difference of 1, so the next consecutive integer must be x+1, and the next is x+2. Since they all add up to -135, we can form this equation: x+x+1+x+2=-132. When you solve, x should be -45, which is the smallest in the set. So the next must be -45+1=-44, and the next is -44+1 which is -43.
Bear in mind that multiplying anything, and anything whatsoever by 1, has a product of the anything itself.
so, let's multiply 2/3 by 1 then and check about,
