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3 years ago

If the speed limit on a highway is 70 miles per hour, about how fast is this in miles per minute?

Mathematics

1 answer:

lara31 [8.8K]3 years ago

5 0

70mi/1hr x 1hr/60min x 1min/60sec= .0194/1sec

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Select the correct answer from each drop-down menu.<br>Shape I is similar to shape II.

SIZIF [17.4K]

Answer:

Translation (moving the figure) will map figure 1 onto figure 2 and then after this , dilation by a scale factor of "2"

3 0

3 years ago

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Which fraction is less than 1 chose all of the correct answer, and explain why you chose and write it down and explain your answ

EleoNora [17]

Answer:

$(3/4)$ and $(2/3)$ .

Step-by-step explanation:

For a fraction of the form $(p / q)$ , the number in front of the division ( $p$ ) is the numerator. The number after the division ( $q$ ) is the denominator.

$\begin{aligned} \frac{p}{q} \quad \genfrac{}{}{0}{}{(\text{numerator})}{(\text{denominator})}\end{aligned}$ .

A positive fraction $(p/q)$ ( $p,\, q > 0$ ) is less than $1$ as long as the numerator $p$ is smaller than the denominator $q$ (that is, $p < q$ .) The reason is that as long as $p,\, q > 0$ :

$\begin{aligned} & \frac{p}{q} < 1 \\ \iff & (q)\, \left(\frac{p}{q}\right) < (q)\, (1) && (\text{given that $q > 0$}) \\ \iff & p < q\end{aligned}$ .

For example, in the fraction $(2/3)$ , $2$ is the numerator while $3$ is the denominator. Both the numerator and the denominator are positive, while the numerator $2\!$ is smaller than the denominator $3\!$ . Therefore, $(2/3)$ would be less than $1$ .

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1 year ago

Mary is traveling cross country on a road trip. So far, Mary has traveled 200 miles in her car and 200 miles by train. The car t

VikaD [51]

Answer:

i dont know i think it is 11?!? srry if im wrong

Step-by-step explanation:

5 0

3 years ago

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NEED HELP ASAP PLEASE

professor190 [17]

No idea sorry! If I knew I would tell you

7 0

1 year ago

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Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6

yan [13]

Each curve completes one loop over the interval $0\le t\le2\pi$ . Find the intersections of the curves within this interval.

$6-6\sin\theta=6\implies 1-\sin\theta=1\implies \sin\theta=0\implies \theta=0,\theta=\pi$

The region of interest has an area given by the double integral

$\displaystyle\int_\pi^{2\pi}\int_6^{6-6\sin\theta}r\,\mathrm dr\,\mathrm d\theta$

equivalent to the single integral

$\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta$

which evaluates to $9\pi+72$ .

8 0

3 years ago