Answer:
Explanation:
The expected product is MgO, so the 1-to-1 mole ratio Mg to O in the product is all that is required.
Answer:
48.37514 kj
Explanation:
Given data:
Mass of water = 163 g
Initial temperature = 29°C
Final temperature = 100°C
Heat added = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = Final temperature - initial temperature
ΔT = 100°C - 29°C
ΔT = 71°C
Q = 163 g × 4.18 j/g.°C × 71°C
Q = 48375.14 j
Joule to Kj conversion:
48375.14 /1000 = 48.37514 kj
Answer: The answer is 167
Explanation: This is because that was right on edg. so yea heart this tho plsss
A Wooden Spoon is your answer because metal attracts heat more, so it would get hotter.
The wooden spoon would not, so you would use that.
Glad I could help, and good luck!
Hepta is seven and tetra is four, so option c is your answer
