We know, x+y = 180
A.T.Q, x = 3y, y= x/3
substitute the value of y,
x+x/3 = 180
4x = 540
x = 540/4
x=135
The answer is
D. in a straightforward, objective manner
Answer:
The distance that the racecar traveled is indeed 500m. But at the end of the lap, it is right back where it started. So overall, it has been displaced 0m.
Explanation:
I believe the car because it has the most mass
Answer:
the speed of the car moving after accelerating for 56 m is 20 m/s
Explanation:
The computation is shown below:
As we know that
Vf^2 = Vi^2 + 2ad
= ( 8m/s )^2 + 2 ( 3m/s2 ) ( 56m)
= 400 m2/s2
Vf = 20 m/s
Hence, the speed of the car moving after accelerating for 56 m is 20 m/s