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maksim [4K]
3 years ago
13

What is the drivers displacement at the end of the lap

Physics
1 answer:
NeX [460]3 years ago
4 0

Answer:

The distance that the racecar traveled is indeed 500m. But at the end of the lap, it is right back where it started. So overall, it has been displaced 0m.

Explanation:

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A ball is launched from ground level at 20 m/s at an angle of 40° above the
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(a) The ball's height <em>y</em> at time <em>t</em> is given by

<em>y</em> = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve <em>y</em> = 0 for <em>t</em> :

0 = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

0 = <em>t</em> ((20 m/s) sin(40º) - 1/2 <em>g t</em> )

<em>t</em> = 0   or   (20 m/s) sin(40º) - 1/2 <em>g t</em> = 0

The first time refers to where the ball is initially launched, so we omit that solution.

(20 m/s) sin(40º) = 1/2 <em>g t</em>

<em>t</em> = (40 m/s) sin(40º) / <em>g</em>

<em>t</em> ≈ 2.6 s

(b) At its maximum height, the ball has zero vertical velocity. In the vertical direction, the ball is in free fall and only subject to the downward acceleration <em>g</em>. So

0² - ((20 m/s) sin(40º))² = 2 (-<em>g</em>) <em>y</em>

where <em>y</em> in this equation refers to the maximum height of the ball. Solve for <em>y</em> :

<em>y</em> = ((20 m/s) sin(40º))² / (2<em>g</em>)

<em>y</em> ≈ 8.4 m

8 0
3 years ago
You need to determine the density of a ceramic statue. if you suspend it from a spring scale, the scale reads 32.4 n . if you th
Mandarinka [93]
Well, the density of the water is
{1000 \frac{kg}{ {m}^{3} } }
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Which statement correctly compares the valence electrons for atoms of francium (Fr) and barium (Ba)?
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Answer:

Francium has fewer valence electrons, but they are in a higher energy level

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3 years ago
Read 2 more answers
PLEASE HELP
worty [1.4K]

Explanation:

by momentum conservation

64× v=42×3.11

v=2.04m/s

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3 years ago
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PLEASE HELP AND HURRY
andreyandreev [35.5K]
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I took the tests earlier hope this helps
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