Answer:
13.12°
Explanation:
Parameters given:
Magnetic field strength, B = 0.350 T
Current in the wire, I = 3.5 A
Force per unit length, F/L = 0.278 N/m
The force on a wire due to the presence of a magnetic field is given as:
F = I*L*B*sinФ
where Ф = angle between the magnetic field and current
The force per unit length, F/L, will be:
F/L = I*B*sinФ
0.278 = 3.5 * 0.35 * sinФ
=> sinФ =
sinФ = 0.227
Ф =
Ф = 13.12°
The angle between the magnetic field and the current is 13.12°.
Complete Question
A field mouse trying to escape a hawk runs east for 5.0m, darts southeast for 3.0m, then drops 1.0m down a hole into its burrow. What is the magnitude of the net displacement of the mouse?
Answer:
The values is
Explanation:
From the question we are told that
The distance it travels eastward is
The distance it travel towards the southeast is
The distance it travel towards the south is
Let x-axis be east
y-axis south
z-axis into the ground
The angle made between east and south is
The displacement toward x-axis is
The displacement toward the y-axis is
Now the overall displacement of the rat is mathematically evaluated as
By definition, the atomic mass of an element is approximately the sum of the mass of protons and neutrons.
Of the choices given, C makes the most sense.
Answer: C) the number of protons and neutrons in an atom.
The solution would be like
this for this specific problem:<span>
KCL at Junction a. </span><span>
<span>+ I1 + I2 + I3 = 0 (1) </span>
<span>KVL
<span>+ 13 V - 0.2 R I1 - 0.025 R I1 - 5 V + 0.02 R I2 = 0 (2) </span>
<span>8 + 0.02 I2 = 0.225 I1 </span>
<span>I1 = 35.6 + 0.0889 I2 (2A) </span></span></span>
<span>KVL (bottom loop - CCW
direction) </span><span>
<span>- 0.02 R I2 + 5 V + 0.5 R I3 = 0 (3) </span>
<span>0.5 I3 = -5 + 0.02 I2 </span>
<span>I3 = -10 + 0.04 I2 (3A) </span></span>
<span>Replace
2A and 3A into 1. </span><span>
<span>+ I1 + I2 + I3 = 0 </span>
<span>( 35.6 + 0.0889 I2 ) + I2 + ( -10 + 0.04 I2 ) = 0 </span>
<span>1.129 I2 = -25.6 </span>
<span>I2 = -22.6A </span>
<span>Solve 2A and 3A for other currents. </span>
<span>I1 = 35.6 + 0.0889 I2 = 35.6 + 0.0889 * -22.6 = 33.5A </span>
<span>I3 = -10 + 0.04 I2 = -10 + 0.04 * -22.6 = -10.9A
So the answer is letter D.</span></span>