Solve. x² + 20x + 100 = 50

Mathematics

2 answers:

Katen [24]4 years ago

4 0

x = −10 ± 5√2

tankabanditka [31]4 years ago

3 0

Solve. x²+ 20x + 100 = 50

Subtracting 50 from both sides

$x^{2} +20x+100-50=50-50$

$x^{2} +20x+50=0$

To solve the quadratic equation, let us use quadratic formula

For, $ax^{2} +bx+c=0$ , $x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}$

So, a=1, b=20, c=50

So, we get,

x= $\frac{-20+-\sqrt{20^{2}-4*1*50}}{2*1}$

$x=\frac{-20+-\sqrt{400-200}}{2}$

$x=\frac{-20+-\sqrt{200}}{2}$

$x=\frac{-20+-10\sqrt{2}}{2}$

$x=\frac{-10+-5\sqrt{2}}{1}$

$x=-10+-5\sqrt{2}$

Option(a) Answer

So, x=-10+5 $\sqrt{2}$

or, x=-10-5 $\sqrt{2}$

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One day at a supermarket, 258 fruits were sold in the morning, and 5/6 of the number of fruits sold in the morning were sold in

astra-53 [7]

Answer:

258 fruits.

Step-by-step explanation:

We have been given that one day at a supermarket, 258 fruits were sold in the morning, and 5/6 of the number of fruits sold in the morning were sold in the afternoon.

So the fruits sold in the afternoon will be 5/6 of 258.

$\text{The number of fruits sold in afternoon}=\frac{5}{6}\times 258$

$\text{The number of fruits sold in afternoon}=5\times 43$

$\text{The number of fruits sold in afternoon}=215$ .

Further, we are told that the number of fruits sold in the next afternoon increased by 20% compared to the number of fruits sold in the afternoon the previous day.

So the number of fruits sold in the next afternoon will be:

$\text{The number of fruits sold in next afternoon}=215+(\frac{20}{100}\times 215)$