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Liono4ka [1.6K]
3 years ago
14

Solve. x² + 20x + 100 = 50

Mathematics
2 answers:
Katen [24]3 years ago
4 0
<span>x² + 20x + 100 = 50</span>


x = −10 ± 5√2



tankabanditka [31]3 years ago
3 0

Solve. x²+ 20x + 100 = 50

Subtracting 50 from both sides

x^{2} +20x+100-50=50-50

x^{2} +20x+50=0

To solve the quadratic equation, let us use quadratic formula

For, ax^{2} +bx+c=0 , x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}

So, a=1, b=20, c=50

So, we get,

x=\frac{-20+-\sqrt{20^{2}-4*1*50}}{2*1}

x=\frac{-20+-\sqrt{400-200}}{2}

x=\frac{-20+-\sqrt{200}}{2}

x=\frac{-20+-10\sqrt{2}}{2}

x=\frac{-10+-5\sqrt{2}}{1}

x=-10+-5\sqrt{2}

Option(a) Answer

So, x=-10+5\sqrt{2}

or, x=-10-5\sqrt{2}

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