Horizontal distance x(t) = ut cos θ
x(2) = 102 * 2 * cos 67 = 79.7 ft.
Vertical distance y(t) = ut sin θ - 1/2 gt^2
y(3) = 102 * 2 * sin 67 - 1/2 * 9.8 * (3)^2 = 187.78 - 44.1 = 143.7 ft.
He will have made a hemisphere which is half of a sphere.
<span>The lines are parallel, but with slightly different y-intercepts. The lines are y=2x-5 and y=2x-4.5
The lines are parallel but one crosses the y-axis at 5 and one crosses the y-axis at 4.5.</span>
Option B:
Surface area of the solid is 730 square millimeters.
Solution:
Area of the rectangle = length × breadth
Length of the top net = (25 + 8 + 8) mm = 41 mm
Breadth of the top net = 5 mm
Area of the Top net = 41 mm × 5 mm
= 205 square mm
Area of the second net = 25 mm × 8 mm
= 200 square mm
Area of the third net = 25 mm × 5 mm
= 125 square mm
Area of the bottom net = 25 mm × 8 mm
= 200 square mm
Surface area of the solid = 205 mm + 200 mm + 125 mm + 200 mm
= 730 square mm
Hence surface area of the solid is 730 square millimeters.
Option A is the correct answer.
