X/1= 1/2/3/4
X= 1/2 times 4/3
X= 4/6
X=2/3. Answer
Answer: 39.308 pounds
Step-by-step explanation:
We assume that the given population is normally distributed.
Given : Significance level : ![\alpha: 1-0.98=0.02](https://tex.z-dn.net/?f=%5Calpha%3A%201-0.98%3D0.02)
Sample size : n= 12, which is small sample (n<30), so we use t-test.
Critical value (by using the t-value table)=![t_{n-1, \alpha/2}=t_{11,0.01}=2.718](https://tex.z-dn.net/?f=t_%7Bn-1%2C%20%5Calpha%2F2%7D%3Dt_%7B11%2C0.01%7D%3D2.718)
Sample mean :
Standard deviation : ![\sigma= 20](https://tex.z-dn.net/?f=%5Csigma%3D%2020)
The lower bound of confidence interval is given by :-
![\overline{x}-t_{(n-1,\alpha/2)}\dfrac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D-t_%7B%28n-1%2C%5Calpha%2F2%29%7D%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
i.e. ![55-(2.718)\dfrac{20}{\sqrt{12}}](https://tex.z-dn.net/?f=55-%282.718%29%5Cdfrac%7B20%7D%7B%5Csqrt%7B12%7D%7D)
![=55-15.6923803166\approx55-15.692=39.308](https://tex.z-dn.net/?f=%3D55-15.6923803166%5Capprox55-15.692%3D39.308)
Hence, the lower bound for the 98% confidence interval for the mean yearly sugar consumption= 39.308 pounds
This sequence is after 3 digits so net 2 digits are
13,17
Sum of 1st cube no N th triangle no
Answer:
if your looking for what the temperature is now then it is -13 Fahrenheit