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Makovka662 [10]
3 years ago
8

The critical points of a rational inequality are x = –4 and x = 2. Which set of points can be tested to solve the inequality?

Mathematics
2 answers:
Alexxandr [17]3 years ago
7 0
-5, 0, 3
You need to test a point at each interval
RoseWind [281]3 years ago
3 0

answer:

C. x = –5, x = 0, and x = 3

hope this helps! :o)

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The sum of three numbers is 12. The sum of twice the first​ number, 5 times the second​ number, and 6 times the third number is
Ede4ka [16]
A suitable calculator can row-reduce the augmented matrix.

first number: 3
second number: 1
third number: 8

5 0
3 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
Solve by inspection: X+4=15
amid [387]

x + 4 = 15

- 4        -4

x = 11

You would subtract 4 because you need to isolate the x to get the value of x. You would subtract it to both sides because whatever you do on one side, you have to do it to the other side.

7 0
3 years ago
Read 2 more answers
What is the length of the hypotenuse, c? Round your answer to the nearest hundredth.
Afina-wow [57]

Answer:

Step-by-step explanation:

By using the Pythagorean theorem:

b^2+3^2=5^2
b^2+9=25

b=sqrt (25-9)

b=sqrt(16)

b=4

=> 4^2+7^2=c^2
16+49=c^2
65=c^2
=>c=sqrt(65)

c = (approximately) 8

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2 years ago
Help pls this has been bugging me for so long and I need the quickest answers please I need answers done by 12:24 nothing to rus
Yanka [14]

Answer:

I'm pretty sure its 350mL

6 0
3 years ago
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