<h2>Answer:</h2>
The correct option is Pf = Pi
<h2>Explanation:</h2>
Momentum is the product of velocity and mass of an object. It is a physical quantity and the law of conservation of momentum says that for a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision. So simply it means that Pf = Pi.
MB₂H₆: 2×11g+6×1g= 28 g/mol
...................
B₂H₆ + 3O₂ ---> 2HBO₂ + 2H₂O
28g.......................................2 mol......
28g B₂H₆ ---- 2 mol H₂O
19,2g B₂H₆ --- X
X = (2×19,2)/28
X = 1,37 mol H₂O
Covelant molecules are formed d
<u>Answer:</u> The moles of carbon dioxide formed in the reaction is 20 moles.
<u>Explanation:</u>
We are given:
Number of moles of butane = 5.0 moles
The chemical reaction for the combustion of butane follows the equation:
![2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(l)](https://tex.z-dn.net/?f=2C_4H_%7B10%7D%28g%29%2B13O_2%28g%29%5Crightarrow%208CO_2%28g%29%2B10H_2O%28l%29)
As, oxygen is present in excess. So, it is considered as an excess reagent.
Thus, butane is considered as a limiting reagent because it limits the formation of products.
By stoichiometry of the reaction:
2 moles of butane produces 8 moles of carbon dioxide.
So, 5 moles of butane will produce =
of carbon dioxide.
Hence, the moles of carbon dioxide formed in the reaction is 20 moles.