Let's use the quadratic formula
a = 1, b = 0, c = -18
This is now split into two equations:
and
Since
The answer is
which means there are 2 real number solutions to the problem: answer B.
Answer:
all real numbers greater than or equal to -1
Step-by-step explanation:
In order to solve this problem we need to know the vertex and the direction its pointing.
First we expand,
x^2-6x+8
To find the x value of the vertex we use this formula (-b/2a).
-(-6)/2(1) = 3
Now we plug 3 in the equation to get the y value,
(3)^2 - 6(3) + 8 = 9 - 18 + 8 = -1
The vertex is (3,-1)
We know the graph points up because x^2 is positive
The vertex is the lowest point, so we now know that -1 is the starting range and if the graph is pointing up, that means all values greater than -1.
This leads to our answer all real numbers greater than or equal to -1.
Answer:
A' will be located 10 units from point A along ray PA
Step-by-step explanation:
we know that
The scale factor is equal to 3
To obtain PA', multiply PA by the scale factor
so
PA'=PA*3
PA=5 units
substitute
PA'=(5)*3=15 units
AA'=PA'-PA=15-5=10 units
therefore
A' will be located 10 units from point A along ray PA
The answer is option C. 9xy sqrt 2x
