Answer:
3, 5, 7, 9, 11, .........
Step-by-step explanation:
Given
= n(n + 2) , then
S₁ = 1(1 + 2) = 1(3) = 3 ⇒ a₁ = 3
S₂ = 2(2 + 2) = 2(4) = 8
S₃ = 3(3 + 2) = 3(5) = 15
Thus
a₂ = S₂ - S₁ = 8 - 3 = 5
a₃ = S₃ - S₂ = 15 - 8 = 7
The first 3 terms are 3, 5, 7
This is an AP with common difference d = 2, then
a₄ = a₃ + 2 = 7 + 2 = 9
a₅ = a₄ + 2 = 9 + 2 = 11
and so on
Answer:
0.209205
Step-by-step explanation:
I put it in the calculator and got this...
Answer:
Step-by-step explanation:
First, multiply both sides by -4. You must also change the inequality sign since you are multiplying both sides by a negative number.
Subtract 1 from both sides.
6 - 1/2z = 2/3
subtract 6 from both sides
- 1/2z = -16/3
divide both sides by -1
1/2z = 16/3
rewrite
1z/2 = 16/3
multiply both sides by 2
1z = 32/3
z = 32/3 or 10 2/3
Hope this helps :)
<span>The sum of two numbers is 48.
a + b = 48
;
If one third of one number is 5 greater than one sixth of another number,
a = b + 5
multiply both sides by 6, cancel the fractions
2a = b + 30
2a - b = 30
</span><span>use elimination to solve this
a + b = 48
2a - b =30
-------------Addition eliminates b, find a
3a = 78
a =
a = 26
then
26 + b = 48
b = 48 - 26
b = 22</span>
