3. Matthew has a jar of 368 nickels and dimes he has been collecting. The total value of

(TIMED HELP) The population model describing the population of antelope in an area is:

Elena L [17]

Answer:

Step-by-step explanation:

The population model describing the population of antelopes in the area is

Pn+1 = [1.75(Pn)^2/(Pn-1)] + 32 - Pn

where n represents the number of years.

In the first year, the number of antelopes is given as 89, to find the number of antelopes for the second year, it means we are looking for P(1+1) = P2. We will substitute 1 for n and 89 for Pn+1

It becomes

Pn+1 = [1.75(Pn)^2/(Pn-1)] + 32 - Pn

P2 = [1.75×89^2 / (89 - 1)] + (32 -89)

P2 = [13861.75 / 88] - 57

P2 = 101

To find P3, we will substitute 101 for Pn+1 and 2 for n. It becomes

P3 = [1.75×101^2 / (101 - 1)] + (32 -101)

P3 = [17851.75 / 100] - 69

P3 = 110

To find P4, we will substitute 110 for Pn+1 and 3 for n. It becomes

P4 = [1.75×110^2 / (110 - 1)] + (32 -110)

P4 = [21175 / 109] - 78

P4 = 116

To find P5, we will substitute 116 for Pn+1 and 4 for n. It becomes

P5 = [1.75×116^2 / (116 - 1)] + (32 -116)

P5 = [23548 / 115] - 84

P5 = 121

To find P6, we will substitute 121 for Pn+1 and 5 for n. It becomes

P6 = [1.75×121^2 / (121 - 1)] + (32 -121)

P6 = [25621.75 / 120] - 89

P6 = 125

To find P7, we will substitute 125 for Pn+1 and 6 for n. It becomes

P7 = [1.75×125^2 / (125 - 1)] + (32 -125)

P7 = [27343.75 / 124] - 93

P7 = 128

To find P8, we will substitute 128 for Pn+1 and 7 for n. It becomes

P8 = [1.75×128^2 / (128 - 1)] + (32 -128)

P8 = [28672 / 127] - 96

P8 = 130

To find P9, we will substitute 130 for Pn+1 and 7 for n. It becomes

P9 = [1.75×130^2 / (130 - 1)] + (32 -130)

P9 = [29575 / 129] - 98

P9 = 131

To find P10, we will substitute 131 for Pn+1 and 7 for n. It becomes

P10= [1.75×131^2 / (131 - 1)] + (32 -131)

P10= [30031.75 / 130] - 99

P10 = 132

The correct option is C

6 0

3 years ago

Tickets to the movies cost $9.50 for adults and $6.50 for kids. A large group bought 12 tickets and spent a total of $87. How ma

Jet001 [13]

Answer:

12

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Which function is a shrink of the exponential growth function shown on the graph?

galina1969 [7]

The answer of this question is B.

5 0

3 years ago

Read 2 more answers

Help me on this Please

Alja [10]

Pythagorean Theorem:
a^2 + b^2 = c^2
Since you have the hypotenuse, you can change the equation to find the missing side.
a^2 - c^2 = - b^2
Insert your numbers:
9^2 - 10^2 = -b^2
What do you get?

6 0

2 years ago

Use the Euclidean Algorithm to demonstrate that 621 and 82 are relatively prime to each other. Explain.

8090 [49]

Answer:

621 and 82 are relatively prime.

Step-by-step explanation:

Two integers are relatively prime (or coprime) if there is no integer greater than one that divides them both (that is, their greatest common divisor is one).

The greatest common divisor of two integers a and b is the largest integer that divides them both.

The Euclidean algorithm is an efficient method for computing the greatest common divisor of two integers, without explicitly factoring the two integers.

The Euclidean algorithm solves the problem:

Given integers a, b find $d=gcd(a,b)$

The Euclidean algorithm provides a fast way to determine d without knowing the prime factors of a or b. Here is an outline of the steps:

Let $a=x$ , $b=y$
Given x, y, use the division algorithm to write $x=yq+r, \quad 0\leq r\leq |y|$ .
If r = 0, stop and output y; this is the gcd of a, b.
If $r \neq 0$ , replace (x, y) by (y, r). Go to step 2.

The division algorithm is an algorithm in which given 2 integers N and D, it computes their quotient Q and remainder R.

Let's say we have to divide N (dividend) by D (divisor). We will take the following steps:

Step 1: Subtract D from N repeatedly until we get a result that lies between 0 (inclusive) and D (exclusive) and is the smallest non-negative number obtained by repeated subtraction.

Step 2: The resulting number is known as the remainder R, and the number of times that D is subtracted is called the quotient Q.

Applying the above steps,

$621-82=539\\539-82=457\\457-82=375\\375-82=293\\293-82=211\\211-82=129\\129-82=47\\\\621=82\cdot7+47$

$621 = 82\cdot 7 + 47\\ 82 = 47\cdot 1 + 35\\ 47 = 35\cdot1 + 12\\ 35 = 12\cdot2 + 11\\ 12 = 11\cdot1 + 1\\ 11 = 1\cdot11 + 0$

The gcd(621, 82) is 1. Therefore, 621 and 82 are relatively prime.

5 0

2 years ago