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Kitty [74]
3 years ago
12

✨Please help✨ (math)

Mathematics
1 answer:
egoroff_w [7]3 years ago
5 0

Answer:

im doing that too </3 plz

Step-by-step explanation:

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Solve each given equation and show your work. Tell whether each question has one solution, an infinite number of solutions, or n
laiz [17]
2x + 4(x - 1) = 2 + 4x
2x + 4x - 4 = 2 + 4x
6x - 4 = 2 + 4x
6x - 4x = 2 + 4
2x = 6
x = 3........there is 1 solution

25 - x = 15 - (3x + 10)
25 - x = 15 - 3x - 10
25 - x = -3x + 5
3x - x = 5 - 25
2x = - 20
x = -20/2
x = -10.....there is 1 solution

4x = 2x + 2x + 5(x - x)
4x = 4x + 5x - 5x
4x = 4x......this has infinite solutions

learn this...
if ur equation ends in a variable equaling a number, then there is one solution.
if ur equation ends in something not equal, like 2 = 4, or 4 = 6, then there is 0 solutions.
if ur equation ends in something equal to something,(the same) like 2 = 2, or 4x = 4x, then there is infinite solutions

3 0
3 years ago
Evaluate 2 + 4/5 n for n = 1/4
Sophie [7]

Answer:

2\frac{1}{5}

Step-by-step explanation:

4 0
3 years ago
If a = 2.4 units, b = 4 units, c = 6 units, and d = 8 units, what is the volume of the two prisms? plzzzzzzzzzzzzzzzzzzzzz helpp
HACTEHA [7]

Answer:

The answer would be

99.2

7 0
4 years ago
Given the graph of log y=log(2)x. Find the area of the three inscribed rectangles
evablogger [386]

Answer: 6+2log_{2} 6

Step-by-step explanation:

S=s_{1} +s_{2} +s_{3} = 2(h_{1} +h_{2} +h_{3} )

h_{1} = log_{2}2=1

h_{2} = log_{2}4=2

h_{3} = log_{2}6

S = 2(1+2+log_{2}6) = 6+2log_{2}6

8 0
3 years ago
Will mark brainlist<br><br> -2 2/3 + -3 3/4 =<br><br> -6 2/7 + 3 1/14 =<br><br> -12 + 4 3/5 =
galben [10]

-12 + 4 3/5 = -7.4 <--- decimal.

-6 2/7 + 3 1/14 = 3 3/14 <--- repeating decimal.

-2 2/3 + -3 3/4 = -6 5/12 <--- repeating decimal.

°.✩┈┈┈┈∘*┈┈୨♡୧┈┈*∘┈┈┈┈✩.°

I hope this helps you. It kind of helps me because, I wanna scream and cry and just stay in one room. So imma go outside and sit down.. and walk back to my room and scream into a pillow (っ◞‸◟c)

3 0
3 years ago
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