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dangina [55]
3 years ago
7

How do I do problems like this???!

Mathematics
1 answer:
NeX [460]3 years ago
4 0

Answer:

Read it

Step-by-step explanation:

read it

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Can someone explain how im meant to do this please? :)
valina [46]

Answer:

you have to do

92×98=9016

then 9016=10(here we roud to 1 signification figure)

49×138=6762

6762=6

216×876=189216

189216=1

i think it’s the answers

7 0
3 years ago
Find the product or type<br>"impossible".<br>3 -5 4 2<br>​
katrin2010 [14]

Answer:

The product of \begin{pmatrix}3&-5\\ \:1&7\end{pmatrix}\begin{pmatrix}4&2\\ \:-4&2\end{pmatrix} is \begin{pmatrix}32&-4\\ -24&16\end{pmatrix}.

Step-by-step explanation:

A matrix is a rectangular arrangement of numbers into rows and columns.

Matrix multiplication refers to the product of two matrices.

The main condition of matrix multiplication is that the number of columns of the 1st matrix must equal to the number of rows of the 2nd one.

To find the product of \begin{pmatrix}3&-5\\ \:1&7\end{pmatrix}\begin{pmatrix}4&2\\ \:-4&2\end{pmatrix}

\mathrm{Multiply\:the\:rows\:of\:the\:first\:matrix\:by\:the\:columns\:of\:the\:second\:matrix}\\\\\begin{pmatrix}3&-5\end{pmatrix}\begin{pmatrix}4\\ -4\end{pmatrix}=3\cdot \:4+\left(-5\right)\left(-4\right)\\\\\begin{pmatrix}3&-5\end{pmatrix}\begin{pmatrix}2\\ 2\end{pmatrix}=3\cdot \:2+\left(-5\right)\cdot \:2\\\\\begin{pmatrix}1&7\end{pmatrix}\begin{pmatrix}4\\ -4\end{pmatrix}=1\cdot \:4+7\left(-4\right)\\\\\begin{pmatrix}1&7\end{pmatrix}\begin{pmatrix}2\\ 2\end{pmatrix}=1\cdot \:2+7\cdot \:2

\begin{pmatrix}3&-5\\ 1&7\end{pmatrix}\begin{pmatrix}4&2\\ -4&2\end{pmatrix}=\begin{pmatrix}3\cdot \:4+\left(-5\right)\left(-4\right)&3\cdot \:2+\left(-5\right)\cdot \:2\\ 1\cdot \:4+7\left(-4\right)&1\cdot \:2+7\cdot \:2\end{pmatrix}

\mathrm{Simplify\:each\:element}\\\\\begin{pmatrix}3&-5\\ 1&7\end{pmatrix}\begin{pmatrix}4&2\\ -4&2\end{pmatrix}=\begin{pmatrix}32&-4\\ -24&16\end{pmatrix}

6 0
4 years ago
What is the solution of x+5-√3−1=−4 ?
umka2103 [35]
B is the answer i'm pretty sure. Hope this helps!!
4 0
4 years ago
Help me please, I need help I don’t understand this problem
jarptica [38.1K]

The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.

<u>Step-by-step explanation:</u>

  • The equation for the maximum speed, s is given by s²= (16/9)x
  • where, x is the length of the water line in feet.

It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.

The question is asked to find the maximum speed when the length of the water is 30 feet.

Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.

<u>Now, calculating the maximum speed :</u>

s² = (16/9)(30)

s² = 480 / 9

s² = 53.3

Taking square root on both sides,

s = √53.3

s = 7.3

The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.

6 0
4 years ago
Please help will mark brainlist please and thank you
rosijanka [135]

Answer:

c

Step-by-step explanation:

and the answer is c

4 0
3 years ago
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