Answer:
the maximum length of specimen before deformation is found to be 235.6 mm
Explanation:
First, we need to find the stress on the cylinder.
Stress = σ = P/A
where,
P = Load = 2000 N
A = Cross-sectional area = πd²/4 = π(0.0037 m)²/4
A = 1.0752 x 10^-5 m²
σ = 2000 N/1.0752 x 10^-5 m²
σ = 186 MPa
Now, we find the strain (∈):
Elastic Modulus = Stress / Strain
E = σ / ∈
∈ = σ / E
∈ = 186 x 10^6 Pa/107 x 10^9 Pa
∈ = 1.74 x 10^-3 mm/mm
Now, we find the original length.
∈ = Elongation/Original Length
Original Length = Elongation/∈
Original Length = 0.41 mm/1.74 x 10^-3
<u>Original Length = 235.6 mm</u>
Answer: (B) 100
Explanation:
Given that;
Pstatic = 20 psig , hz = 160ft, hf = 20ft
Now total head will be;
T.h = hz + hf
T.h= 160 + 20
T.h = 180ft
Minimum pressure = Psatic + egh
we know that specific weight of water is 62.4 (lb/ft3)
so
P.min = (20 bf/in² ) + (62.4 b/ft³ × 180 fr
P.min = (20 bf/in² ) + ( 62.4 × 180 × 1 ft²/144 in²)
P.min = 20 + 78
P.min = 98 lbf/in²
Therefore the minimum pressure rating (psi) of the piping system is most nearly B) 100
Answer:
Explanation:
Brooding can simply defined as. “Application of heat to the birds at early part of their life”. Brooding is the care of young chicks by provision of optimum environment. The temperature by external heat source provided until the chicks not become able to regulate its body temperature efficiently.09-May-2018
The amount that a dealership pays a manufacturer for a car is essentially its invoice price.
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Answer:
3.42 kW
Explanation:
calculate the mass flow rate of the water = density * velocity * area
= 13.3 kg/s
where Area of pipe = π/4 * d^2 = π/4 * 0.075^2 m = 0.0044 m^2
given that : 1 Kg = 1 N s^2 / m, 1 Watt = 1 N m /s
calculate : power produced by discharge pipe
Discharge Pressure x Volume flow =
Pressure * Area * velocity
P * 0.0044 * 3 = 2253 N m /s
calculate: power due the mass of water
mass of water * 2 = 258 N m/s
where: mass of water = density * volume
Calculate power produced due the velocity of exiting water
= m * V2/2 = 59.4 N m/s
hence The power added to fluid = 2253 watts
power added to the fluid by pump = 2253 / 0.75 = 3.42 kW