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tiny-mole [99]
3 years ago
15

You have a piece of 1045 steel 80 cm long and 30 cm wide and 15cm high. In this piece it is desired to make a groove along the 8

0 cm with a width of 8 cm with a depth of 10 cm. Calculate the progress that the tool must have to make the groove in a time of 5 minutes. It assumes that for this operation an End Mill Flat tool of 4 mm diameter is used and its maximum axial cutting capacity is 50 mm.
Engineering
1 answer:
tino4ka555 [31]3 years ago
4 0

Answer:

0.65 m/min

Explanation:

The volume of material to be removed is

80*8*10 = 650 cm^3

The tool has a diameter of 4 mm and a maximum axial cutting capacity of 50 mm, so its cross section normal to advance is

0.4*5 = 2 cm^2

If the groove have to be made in T = 5 minutes the advance speed would be

V/(S * T)

650/(2 * 5) = 65 cm/min = 0.65 m/min

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