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Radda [10]
3 years ago
10

PLEASE HELP!! 100 POINTS!! BRAINLIEST!! What is the GCF of the terms in the numerator and denominator? Rewrite the expression by

factoring out any common factors. Write the quadratic expressions in the numerator and the denominator in factored form. Cancel the common factor of the numerator and the denominator to write the expression in simplified form.
4x^2-14x+6/x^3-7x^2+12x
Mathematics
1 answer:
saul85 [17]3 years ago
6 0

Answer:

2(2x-1)/x(x-4)

Step-by-step explanation:

4x^2-14x+6/x^3-7x^2+12x

2(2x^2-7x+3)/x(x^2-7x+12)

2(2x^2-6x-x+3)/x(x^2-4x-3x+12)

2(x-3)(2x-1)/x(x-4)(x-3)

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4 0
3 years ago
Which of the following points lies on the circle whose center is at the origin and whose radius is 10?
Nonamiya [84]

Answer:

Step-by-step explanation:

b

8 0
2 years ago
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Please help me out with these no one is helping me.<br>Please anyone <br>​
Olin [163]

Answer:

Below.

Step-by-step explanation:

You find the values of y by substituting the values of x in the expression x^2 + 3x - 1.

So f(-4) = (-4)^2 + 3(-4) - 1 = 16-12-1 = 3

in the same way  f(-3) = -1, f(-2) = -3, f(-1) = -3,

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Now plot the points (-4, 3) , (-3, -1) and so on  

Then you can read the values off this graph.

8 0
3 years ago
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if 18 meters of high resistance wire with a diameter of 1.2 mm has a resistance of 10 ohms, what is the resistance of 27 m of th
Stells [14]
The electrical resistance of a wire varies as its length and inversely as the square of the diameter.
R = (k*L)/(d^2)
where k = proportionality constant
Since the two wires have the same material, their proportionality constant is same.
Equating that
(R1*d1^2)/L1 = (R2*d2^2)/L2

Given that R1 = 10 ohms, d1 = 1.2 mm or 0.0012 m, L1 = 18 m, d2 = 1.5 mm or 0.0015 m, L2 = 27 m, and R2 is unknown.
Therefore
[10*(0.0012^2)]/18 = [R2*(0.0015^2)]/27
R2 = 9.6 ohms 
6 0
3 years ago
PLEASE HELP ASAP!!!
ZanzabumX [31]

Answer:

should be 2 excluding the start (origin)

Step-by-step explanation:

3 0
3 years ago
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