Joshua's rule was to add 2/6 or 1/4 (same thing) to the previous number. The missing number in Joshua's sequence is 1 1/6.
For this parabola we have:
f ( 0 ) = 8
and : f ( 1 ) = 24
In the first equation ( A) :
f ( 0 ) = - 16 * ( 0 - 1 )² + 24 = - 16 * 1 + 24 = 8 ( correct )
f ( 1 ) = - 16 * ( 1 - 1 )² + 24 = 24 ( correct )
For B:
f ( 0 ) = - 16 * ( 0 + 1 )² + 24 = - 16 + 24 = 8 ( correct )
f ( 1 ) = - 16 * ( 1 + 1 )² + 24 = - 16 * 4 + 24 = - 64 + 24 = 40 ( false )
For C:
f ( 0 ) = - 16 * ( 0 - 1 )² - 24 = - 16 - 24 = - 40 ( false )
f ( 1 ) = - 16 * ( 1 - 1 )² - 24 = - 24 ( false )
For D:
f ( 0 ) = - 16 * ( 0 + 1 )² - 24 = - 16 - 24 = - 40 ( false )
f ( 1 ) = - 16 * ( 1 - 1 )² - 24 = - 24 ( false )
Answer:
A ) f ( t ) = - 16 * ( t - 1 )² + 24
1)360 (400*.9)
2)342 (380*.9)
3)119 (140*.85)
4)28 (35*.8)
Answer:
M=3*2
M=6
Step-by-step explanation:
Answer:
Step-by-step explanation:
hello :
an equation of this graph is : f(x) = a(x-h)²+k when (h,k) the vertex
so : h=5 and k= -4
f(x) = a(x-5)²-4....... now calculate : a
the y- intercept is : - 6.5 means : f(0) = - 6.5
put x=0 and f(x) = - 6.5
you have : -6.5 = a(0-5)²-4
-6.5 = 25a - 4
25a = -2.5 so : a= -2.5/25= 1/10
the equation is :
<h2>f(x) = (1/10)(x-5)²-4</h2>
