Molar mass KBr = 119 g/mol
Volume in liters: 250.0mL / 1000 => 0.25 L
n = M x V
n = 1.20 x 0,25 => 0.3 moles of KBr
Therefore:
1 mole KBr ----------- 119 g
0.3 moles KBr -------- ??
0.3 x 119 / 1 => 35.7 g of KBr
S, Sulfur. An easy way to find the answer is simply looking at the last set of numbers.
Answer:
0.7692 M ≅ 0.77 M.
Explanation:
- It is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.
<em>(MV) before dilution = (MV) after dilution.</em>
M before dilution = 2.0 M, V before dilution = 0.25 L.
M after dilution = ??? M, V after dilution = 0.25 L + 0.40 L = 0.65 L.
∴<em> M after dilution = (MV) before dilution/(V) after dilution</em> = (2.0 M)(0.25 L)/(0.65 L) =<em> 0.7692 M ≅ 0.77 M.</em>
The law of conservation holds that mass can not be destroyed but can only take on different forms. So if 5 g of water becomes a gas it becomes 5 g of water vapor. The mass of the liquid water is simply transferred into the mass of the newly formed water vapor.
