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myrzilka [38]
3 years ago
15

What is the symbol for Phosphorus on the periodic table of the elements?

Chemistry
2 answers:
Rufina [12.5K]3 years ago
7 0
P is the symbol
Hope this helped :)
Delicious77 [7]3 years ago
5 0
On the periodic table, Phosphorus is P.
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Liquid octane (CH) has a density of 0.7025 g/mL at 20 °C. Find the true mass (murue) of octane when the mass weighed in 18 air i
Goshia [24]

Explanation:

According to Buoyance equation,

          m = [m' \times \frac{1 - \frac{d_{a}}{d_{w}}}{1 - \frac{d_{a}}{d}}]

where,      m = true mass

                 m' = mass read from the balance = 17.320 g

              d_{a} = density of air = 0.0012 g/ml

              d_{w} = density of the balance = 7.5 g/ml

                    d = density of liquid octane = 0.7025 g/ml

Now, putting all the given values into the above formula and calculate the true mass as follows.

      m = [m' \times \frac{1 - \frac{d_{a}}{d_{w}}}{1 - \frac{d_{a}}{d}}]    

          = [17.320 g \times \frac{1 - \frac{0.0012 g/ml}{7.5 g/ml}}{1 - \frac{0.0012 g/ml}{0.7025}}]

          = 17.320 g \times 0.999850                

          = 17.317 g

Thus, we can conclude that the true mass of octane is 17.317 g.

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A sample of an unknown compound has a percent composition of 52.14% carbon, 13.13% hydrogen, and 34.73% oxygen. Which compounds
Artemon [7]
<h3>Answer:</h3>

                The two possible compounds are;

                            1) Dimethyl Ether H₃C--O--CH₃

                           2) Ethanol  H₃C--CH₂--OH

<h3>Solution:</h3>

Step 1: Calculate Moles of each Element;

                      Moles of C  =  %C ÷ At.Mass of C

                      Moles of C  =  52.14 ÷ 12.01

                      Moles of C  =  4.341 mol


                      Moles of H  =  %H ÷ At.Mass of H

                      Moles of H  =  13.13 ÷ 1.01

                      Moles of H  =  13.00 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  =  34.73 ÷ 16.0

                      Moles of O  =  2.170 mol

Step 2: Find out mole ratio and simplify it;

                C                                        H                                     O

            4.341                                 13.00                              2.170

     4.341/2.170                      13.00/2.170                    2.170/2.170

               2                                      5.99                                    1

               2                                        6                                       1

Hence,  Empirical Formula  =  C₂H₆O

<h3>Result:</h3>

         As the molecular mass of compound is not given therefore, we can assume and guess the empirical formula to be the molecular formula. Hence, possible compounds are,

                            1) Dimethyl Ether H₃C--O--CH₃

                           2) Ethanol  H₃C--CH₂--OH

3 0
3 years ago
Find the exact value of x
Semmy [17]

Answer:

12

Explanation:

I am not sure this is a simple answer

5 0
3 years ago
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