1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mrs_skeptik [129]
4 years ago
6

The two right scalene triangles shown are similar , but not congruent. Which statement about the triangles is not true

Mathematics
2 answers:
lidiya [134]4 years ago
7 0

Answer:

Third choice.

The right correspondence is \angle CDB \cong \angle ECD

Step-by-step explanation:

The third choice is not true, that is

\angle CDB NOT corresponds to \angle ECD

If \triangle CBD \sim \triangle CDE, then corresponding sides are proportional, and corresponding angles are congruent. The corresponding angle of \angle CDB is

\angle CDB \cong \angle ECD

Therefore, the third option shows a wrong correspondence, that's the right choice in this case, because it doesn't express a valid correspondence.

garri49 [273]4 years ago
3 0

Answer: <CDB corresponds to <ECD

Step-by-step explanation:

The angles in similar triangles correspond to each other.

For two angles in similar triangles to correspond to each other, then they have to be in the same position in the triangle. (EX: a 90 degree angle corresponds to another 90 degree angle or an angle across from the shortest side corresponds to another angle in the other triangle across from the shortest side)

In this case, <CDB is to the right of the 90 degree angle, so the angle it will correspond to is the angle in the other triangle which is opposite to the 90 degree angle, which is <CED.

<CED is not <ECD, so that answer is wrong.

Tell me if I need to clarify anything - this topic is kind of hard to explain :/

You might be interested in
who's better Messi or Ronaldo based on these pictures. when there ratio of shots is m= 500 out of 400 and r=700 out of 3000
jolli1 [7]
Ronaldo................
8 0
3 years ago
Read 2 more answers
What would this problems answer be ?12y=2 1\4
mafiozo [28]

Answer:

Step-by-step explanation:12y ×4 =21

48y=21

Y=0.44

Mark brainlest if correct pls

5 0
4 years ago
If f(x) = 4x – 5 and g(x) = 3 – 2x, find f(x) + g(x).
lubasha [3.4K]
(4x-5)+(2x-3)

4x+2x= 6x
-5+-3= -8

6x-8
3 0
3 years ago
What is y + 9 &lt; -6 ???
FrozenT [24]
Y is less than or equal to -16 i think but I’m not sure
4 0
3 years ago
Tammy learns in science class that water freezes when its temperature is
Oksanka [162]

The required number line that shows all of the possible

temperatures is option A.

<h3>Inequalities and number line</h3>

From the given question, we have that water freezes when its temperature is no more than 32 °F

The statement no more than 32 °F shows that the temperature cannot be greater than 32 but less than or equal to 32. This is written mathematically as;

t ≤ 32.

We are to select the number line that shows all of the possible temperatures. The required number line that shows all of the possible

temperatures is option A.

Learn more on number lines here: brainly.com/question/24644930

7 0
2 years ago
Other questions:
  • Find the ratio of x to y. x/5 2/3 5/y 2/3 4/9 1
    8·1 answer
  • What is the value of n
    11·1 answer
  • An article when sold at a profit of 5% yields Rs 50 more than when sold at a loss of 5%. What was the cost price of the article?
    9·2 answers
  • If n is an odd number greater than or equal to 3, can n + 1 ever be prime? What if n equals 1?
    7·1 answer
  • Enter the value of (1)(-8) (4)​
    13·2 answers
  • Find the simple interest paid to the nearest cent for each principal, interest
    13·1 answer
  • 2x - 7y - 2x – 3y simplify as far as possible​
    7·2 answers
  • Solve the equation:<br> |x+3| &gt;2x-1
    13·2 answers
  • A number y cubed plus x squared decreased by 7
    6·1 answer
  • Write a rule to describe each transformation please I need help asp
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!