Compound J, C16H16Br2, is optically active. On treatment with strong base, compounds K and L (each C16H14) are formed; K and L e
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The answer for the following problem is mentioned below.
- <u><em>Therefore the final moles of the gas is 14.2 × </em></u>
<u><em> moles.</em></u>
Explanation:
Given:
Initial volume () = 230 ml
Final volume () = 860 ml
Initial moles () = 3.8 ×
moles
To find:
Final moles ()
We know;
According to the ideal gas equation;
P × V = n × R × T
where;
P represents the pressure of the gas
V represents the volume of the gas
n represents the no of the moles of the gas
R represents the universal gas constant
T represents the temperature of the gas
So;
V ∝ n
=
where,
() represents the initial volume of the gas
() represents the final volume of the gas
() represents the initial moles of the gas
() represents the final moles of the gas
Substituting the above values;
=
= 14.2 ×
moles
<u><em>Therefore the final moles of the gas is 14.2 × </em></u><u><em> moles.</em></u>
