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mojhsa [17]
3 years ago
12

Carbon-14 is an isotope used in carbon dating. The nucleus becomes Nitrogen-14 through beta decay. Its half-life is 5370 years.

We can use this information to think about the large sample of 14C that is part of all organic matter. We can also think about the fate of a single 14C nucleus, as we did above. a) What information does the half-life give you for a given large sample of 14C nuclei
Chemistry
1 answer:
frosja888 [35]3 years ago
8 0

Answer:

If the half-life of 14C is 5730 years, when this period of time has passed it will have been halved, it is called the exponential decay law of radioactive isotopes.

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What is the electron configuration of ClS2?
miss Akunina [59]

Answer:Chlorine

Explanation:The distribution of electrons in an atom is called as Electronic Configuration. Formula 2n2 helps in the determination of the maximum number of electrons present in an orbit, here n= orbit number. The formula helps in determination of arrangement of electrons and is known as “Bohr Bury Schemes.”

4 0
3 years ago
The electron-domain geometry of a sulfur-centered compound is trigonal bipyramidal. The hybridization of the central sulfur atom
VMariaS [17]

The hybridization state of the central sulfur atom is sp3d.

The valence shell electron pair repulsion theory describes the shape of molecules in terms of the number of electron pairs that surround the valence shell of the central atom in the molecule.

There are certain molecular shapes that are associated with certain hybridization states of the central atom. Since the central sulfur atom is trigonal bipyramidal, the hybridization state is sp3d.

Learn more: brainly.com/question/13978941

8 0
2 years ago
The molar solubility for baco3 is 9.0 x 10-5 m at 25 degrees
Ierofanga [76]
<span> Ksp = [Ba2+][CO32-] = (9.0 X 10⁻⁵)² = 8.1 X 10</span>⁻⁹
8 0
3 years ago
A 4.000 g sample of iron was heated from 0.0°C to 21.0°C. If it has a specific heat of 0.440 kJ/kg °C, how many kilojoules of he
Mashutka [201]
M = 4 g = 4/1000 kg = 0.004 kg, θ₂ = 21.0°C, θ₁ = 0°C , c = 0.44kJ/kg°C,

Q = mc(θ₂ - θ₁)

Q = 0.004*0.440*(21 - 0)

Q  =  0.03696 kJ 

0.03696 kJ<span> of heat is absorbed.</span>
6 0
3 years ago
Given that the frequency of a wave is 9.12x10^-12 Hz, what must be the
polet [3.4K]

Answer:

The wavelength of wave is 0.33 ×10²⁰ m.

Explanation:

Given data:

Frequency of wave = 9.12×10⁻¹² Hz

Wavelength of wave = ?

Solution:

Formula:

Speed of light = wavelength × frequency

c = λ × f

λ = c/f

This formula shows that both are inversely related to each other.

The speed of light is 3×10⁸ m/s

Frequency is taken in Hz.

It is the number of oscillations, wave of light make in one second.

Wavelength is designated as "λ" and it is the measured in meter. It is the distance between the two crust of two trough.

Now we will put the values in formula.

λ = 3×10⁸ m/s  / 9.12×10⁻¹² Hz

Hz = s⁻¹

λ = 0.33 ×10²⁰ m  

The wavelength of radiation is 0.33 ×10²⁰ m  .

5 0
3 years ago
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