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dimaraw [331]
3 years ago
15

Calculate [OH - ] given [H 3 O + ]=1.40x10 -5 M.

Chemistry
1 answer:
Sedaia [141]3 years ago
8 0

Taking into account the definition of pH and pOH, the [OH⁻] is 7.08*10⁻¹⁰ M.

First of all, pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

Being [H₃O⁺]=1.40×10⁻⁵ M, the pH is calculated as:

pH= - log (1.40×10⁻⁵ M)

Solving:

<u><em>pH= 4.85</em></u>

<u><em /></u>

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

The following relationship can be established between pH and pOH:

pOH + pH= 14

Being pH= 4.85, pOH is calculated as:

pOH + 4.85= 14

pOH= 14 - 4.85

<u><em>pOH= 9.15</em></u>

<u><em /></u>

Replacing in the definition of pOH the concentration of OH⁻ ions is obtained:

- log [OH⁻]= 9.15

Solving

[OH⁻]= 10⁻⁹ ¹⁵

[OH⁻]= 7.08*10⁻¹⁰ M

In summary, the [OH⁻] is 7.08*10⁻¹⁰ M.

Learn more:

  • <u>brainly.com/question/16032912?referrer=searchResults</u>
  • <u>brainly.com/question/13557815?referrer=searchResults</u>
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