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3 years ago

Pls Answer really need it

Mathematics

1 answer:

vfiekz [6]3 years ago

7 0

Unit Rate:
6 plants in 1 square yard
Square yard for every 100 grass seeds
8 seeds per square foot
2 plants per square foot

Rate:
25 trees per 25 yards
4 acres for 800 plants

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A city has a population of 210,000 people. Suppose that each year the population grows by 3.25% . What will the population be af

serg [7]

Answer: the population be after 10 years is 289145

Step-by-step explanation:

The growth rate is exponential. We would apply the formula for exponential growth which is expressed as

y = b(1 + r)^t

Where

y represents the population after t years.

t represents the number of years.

b represents the initial population.

r represents rate of growth.

From the information given,

b = 210000

r = 3.25% = 3.25/100 = 0.0325

t = 10 years

Therefore,

y = 210000(1 + 0.0325)^10

y = 210000(1.0325)^10

y = 289145

5 0

3 years ago

I don’t understand how to do this

schepotkina [342]

Answer:

The solution is $x =0.$

Step-by-step explanation:

The equation

$\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2$

can be rewritten as

$2* sin(\dfrac{3\pi }{2} +2) =-2$

and can be further simplified to

$sin(\dfrac{3\pi }{2}+x ) =-1$ .

Now, taking the inverse sine of both sides we get:

$sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)$

$\bold{(2).}\: \dfrac{3\pi }{2} +2 =sin^{-1}(-1)$

The value of the right side on the interval $[0,2\pi)$ is

$sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o)$ ,

which makes the equation (2)

$\dfrac{3\pi }{2}+x =\dfrac{3\pi}{2}$

solving for $x$ gives

$\boxed{x = 0}$

which is our solution.

4 0

3 years ago

What is the solution to the system of equations y= -3x+6 and y =9

Lilit [14]

Plug the value of 9 in for y
9=-3x+6

Subtract 6 from both sides
3=-3x

Divide both sides by -3
-1=x

Final answer: x=–1

7 0

3 years ago

Determine how many solutions if correct bainliest

PolarNik [594]

Answer:

No solutions

Step-by-step explanation:

6x+2y=20

-3x-y=-4 (by rewriting)

6/-3 = 2/-1≠20/-4

-2=-2≠-5

So it has no solutions

5 0

3 years ago

4a/3-b/4=6<br> 5a/6+b=13<br> Solve linear system by elimination

kondor19780726 [428]

$\bf \cfrac{4a}{3}-\cfrac{b}{4}=6
\qquad \qquad 
\cfrac{5a}{6}+b=13
\\\\\\
\textit{let us remove the denominators off those folks}\\
\textit{by multiplying the first one by 12, both sides}\\
\textit{and the second one by 6, both sides, thus}
\\\\\\
12\left( \cfrac{4a}{3}-\cfrac{b}{4} \right)=12(6)\implies 16a-4b=72
\\\\\\
6\left( \cfrac{5a}{6}+b \right)=6(13)\implies 5a+6b=78$

$\bf \textit{now, let's do the elimination}
\\\\

\begin{array}{llll}
16a-4b=72&\boxed{\times 3}\implies &48a-\underline{12b}=216\\\\
5a+6b=78&\boxed{\times 2}\implies &10a+\underline{12b}=156\\
&&--------\\
&&58a+0\quad=372
\end{array}$

solve for "a", once you get "a", plug it back into either equation to get "b"

3 0

3 years ago