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2 years ago

Which equation represents a line which is perpendicular to the line 6x+y=-4

Mathematics

1 answer:

ivanzaharov [21]2 years ago

6 0

Answer:

y = 1/6x - 4

Step-by-step explanation:

y = -6x - 4

current slope is -6 so the slope of a line perpendicular would be 1/6

y = 1/6x - 4

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Write an equation in polnt-slope form for the line through the given point with the given slope of (10,-9); m = -2

jek_recluse [69]

Answer:

y=mx+b

-2(10)+b=-9

b=11

y=-2x+11

5 0

3 years ago

If the numerator and denominator of the fraction is increased by 2an1 respectively; it becomes3/4 if the numerator and the denom

ipn [44]

Answer:

The fraction is $\frac{7}{1}$

Step-by-step explanation:

Let the numerator be x and denominator be y

So, Fraction = $\frac{x}{y}$

Now we are given that numerator and denominator of the fraction is increased by 2 and 1 respectively. it becomes 3/4

So, Fraction becomes : $\frac{x+2}{y+1}=\frac{3}{4}$

$4(x+2)=3(y+1)$

$4x+8=3y+3$

$4x-3y+5=0$ ----1

We are also given that the numerator and the denominator are decreased by 2 and 1 respectively , it becomes 1/2

So, Fraction becomes : $\frac{x-2}{y-1}=\frac{1}{2}$

$2(x-2)=y-1$

$2x-4=y-1$

$2x-y-3=0$ ---- 2

Substitute the value of y from 2 in 1

$4x-3(2x-3)+5=0$

$4x-6x+9+5=0$

$14=2x$

$7=x$

Substitute the value of x in 2

$2(2)-y-3=0$

$4-3=y$

$1=y$

So, Fraction = $\frac{x}{y}=\frac{7}{1}$

Hence The fraction is $\frac{7}{1}$

7 0

3 years ago

rock is thrown upward with a velocity of 27 meters per second from the top of a 23 meter high cliff and it misses the cliff on t

ahrayia [7]

the rock will be at 11 meters from the ground level after 5.92 seconds

Step-by-step explanation:

The motion of the rock is a free-fall motion, since the rock is acted upon the force of gravity only. Therefore, it is a uniformly accelerated motion, so its position at time t is given by the equation:

$y=h+ut+\frac{1}{2}at^2$

where

h = 23 m is the initial height

u = 27 m/s is the initial velocity, upward

$a=g=-9.8 m/s^2$ is the acceleration of gravity, downward

t is the time

We want to find the time t at which the position of the rock is

y = 11 m

Substituting and re-arranging the equation, we find

$11=23+27t-4.9t^2\\4.9t^2-27t-12=0$

This is a second-order equation, which has solutions:

$t=\frac{27\pm \sqrt{(-27)^2-4(4.9)(-12)}}{2(4.9)}=\frac{27\pm \sqrt{964.2}}{9.8}$

$t_1 = -0.41 s$

$t_2=5.92 s$

The first solution is negative so we neglect it: therefore, the rock will be at 11 meters from the ground level after 5.92 seconds.

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

8 0

3 years ago

I give up i might have to pull an allnighter

netineya [11]

Answer:

Yes, they are congruent

Step-by-step explanation:

Yes, they are congruent because all the side and angle lengths are congruent.

6 0

3 years ago

Read 2 more answers

What does 1/4 + 3/4 + 9/8

Katena32 [7]

Answer:

the answer is 17/8

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers