Answer:
(−1.5,1)
Step-by-step explanation:
Finding the distance, midpoint, slope, equation and the x y-intercepts of a line passing between the two points p1 (6,7) and p2 (-9,-5)
The distance (d) between two points (x1,y1) and (x2,y2) is given by the formula
d = √ ((X2-X1)2+(Y2-Y1)2)
d = √ (-9-6)2+(-5-7)2
d = √ ((-15)2+(-12)2)
d = √ (225+144)
d = √ 369
The distance between the points is 19.2093727122985
The midpoint of two points is given by the formula
Midpoint= ((X1+X2)/2,(Y1+Y2)/2)
Find the x value of the midpoint
Xm=(X1+X2)/2
Xm=(6+-9)/2=-1.5
Find the Y value of the midpoint
Ym=(Y1+Y2)/2
Ym=(7+-5)/2=1
The midpoint is: (-1.5,1)
Answer:
option A
Step-by-step explanation:
∠WPS +∠OPW = 180 {straight line}
∠WPS +110 = 180
∠WPS = 180 - 110
∠WPS = 70°
∠RWQ + ∠QWT +∠TWU = 180 {straight line}
∠RWQ + 60 + 50 = 180
∠RWQ + 110 = 180
∠RWQ = 180 - 110
∠RWQ= 70°
∠PWU + ∠USP + ∠ WPS = 180 {angle sum property of triangle}
∠PWU + 40 + 70 = 180
∠PWU + 110 = 180
∠PWU = 180 - 110
∠PWU = 70°
I believe it's A I really hope that's right
Using the Pythagoras theorem
(sqrt 117)^2 = x^2 + 6^2
x^2 = sqrt117)^2 + 6^2
x^2 = 117 - 36 = 81
so x = 9 answer
Answer:
-20
Step-by-step explanation:
