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Liula [17]
3 years ago
7

The image in down there attached

Mathematics
1 answer:
liberstina [14]3 years ago
4 0

Answer:

D

Step-by-step explanation:

For this one, you want to solve it similarly to linear equations.

-13x+11<-24x by adding 24x to both sides becomes 11x<11.

From there, you divide by 11 to isolate x, leaving x<1.

Since the equation has a < symbol (not ≤), the dot is not filled in. X is less than 1, so the arrow goes to the left, making it D.

**This content involves solving and sketching linear inequalities, which you may wish to revise. I'm always happy to help!

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Solve for x. write both solutions, separated by a comma<br> 2x^2-7x-4=0
avanturin [10]
2x^2-7x-4=0

2x^2-8x+x-4=0

2x(x-4)+1(x-4)=0

(2x+1)(x-4)=0

x=-1/2, 4
5 0
3 years ago
Read 2 more answers
On Sunday, a local hamburger shop sold a combined total of 378 hamburgers and cheeseburgers. The number of cheeseburgers was sol
ipn [44]

Answer:

The number of hamburgers sold was 126.

Step-by-step explanation:

Let h = number of hamburgers sold

let c = cheeseburgers sold

c+h = 378

c = 2h

Substitute c =2h into c+h =278

c+h =378

2h+h = 378

Combine like terms

3h = 378

Divide by 3

3h/3 =378/3

h =126

The number of hamburgers sold was 126.

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3 years ago
What is 0.0008235 in scientific notation
larisa [96]
I think this is the Answer

8.235*10^-4

7 0
3 years ago
2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi
Oksana_A [137]

Answer:

(a) E(X) = 950

(b) $ COV = 0.007255$

(c) P(X > 980) = 0.00001\\\\

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$ COV = \frac{\sigma}{E(X)} $

Where the standard deviation is given by

\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892

So the coefficient of variance is

$ COV = \frac{6.892}{950} $

$ COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

P(X > 980)  = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980)  = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980)  = 1 - P(Z < 4.28)\\\\

The z-score corresponding to 4.28 is 0.99999

P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0
3 years ago
Do roll two dice win if the product is a multiple of 3 what are the chances?
Katarina [22]
Answer has been removed
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