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3 years ago

The image in down there attached

Mathematics

1 answer:

liberstina [14]3 years ago

4 0

Answer:

Step-by-step explanation:

For this one, you want to solve it similarly to linear equations.

-13x+11<-24x by adding 24x to both sides becomes 11x<11.

From there, you divide by 11 to isolate x, leaving x<1.

Since the equation has a < symbol (not ≤), the dot is not filled in. X is less than 1, so the arrow goes to the left, making it D.

**This content involves solving and sketching linear inequalities, which you may wish to revise. I'm always happy to help!

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The price of a ticket to the circus this year is 10% more than the price of a ticket to the circus last year. If the variable t

dlinn [17]

Answer:

Option B multiply t with 1.1

Step-by-step explanation:

Let

t------> the ticket price for the circus last year

x-----> the ticket price for the circus this year

we know that

$100\%+10\%=110\%=110/100=1.10$

$x=1.10(t)$

therefore

The ticket price for the circus this year is equal to the ticket price for the circus last year multiplied by 1.10

7 0

3 years ago

The admission fee at a local zoo is $1.50 for children and $5.00 for adults. On a certain day, 3000 people enter the zoo and $9,

vlabodo [156]

1600 children and 1400 adults attended

<h3>How to determine the number of adults?</h3>

Let the children be x and adult be y.

So, we have the following equations:

x + y = 3000

1.5x + 5y = 9400

Make x the subject in x + y = 3000

x = 3000 - y

Substitute x = 3000 - y in 1.5x + 5y = 9400

1.5(3000 - y) + 5y = 9400

Expand

4500 - 1.5y + 5y = 9400

Evaluate the like terms

3.5y = 4900

Divide both sides by 3.5

y = 1400

Substitute y = 1400 in x = 3000 - y

x = 3000 - 1400

Evaluate

x = 1600

Hence, 1600 children and 1400 adults attended

Read more about system of equations at:

brainly.com/question/14323743

#SPJ1

8 0

2 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST !!

murzikaleks [220]

Answer:

<QPM and <QPR

Step-by-step explanation:

adjacent angles have a common vertex and side, and those are the only two that have a common side

hope this helps :)

if it does, can I get brainliest, please??!

3 0

3 years ago

Pete grabbed 18 mixed nuts, 2/9 of which were almonds. Which equation shows how to determine the number of almonds Pete grabbed?

I am Lyosha [343]

Answer:

18 multiplied by 2/9 = 4

Step-by-step explanation:

To determine the number of almonds that Pete grabbed, you have to multiply how much of the nuts were almonds by the total number of nuts that he grabbed. So,

2/9 × 18

= 0.2222 × 18

= 4

Pete grabbed 4 almonds out of the 18 mixed nuts that he grabbed.

Hope that helps.

3 0

4 years ago

Read 2 more answers

Assume that the weights of individuals are independent and normally distributed with a mean of 160 pounds and a standard deviati

Ilia_Sergeevich [38]

Answer:

a) $\bf 0.3446^{25}=2.7095*10^{-12}$

b) 3,624.25 pounds

Step-by-step explanation:

Since 4300/25 = 172, in average every single person should weight 172 pounds to exceed the design limit.

The probability that one person weights 172 pounds or more is the area under the Normal curve with mean 160 pounds and standard deviation 30 pounds to the right of 172.

In Excel and OpenOffice Calc, this value is found with the formula

=1-NORMDIST(172;160;30;1)

(NORMDIST(172;160;30;1) gives the area to the left of 172, so 1-NORMDIST(172;160;30;1) gives the area to the right of 172)

and equals 0.3446

(see picture 1)

Hence, the probability that all the 25 people exceeds 172 pounds equals

$\bf 0.3446^{25}=2.7095*10^{-12}$

Similarly, we must find a weight w such that if p is the area to the left of w, then

$\bf p^{25}>0.0001$

$\bf p=\sqrt[25]{0.0001}=0.6918$

w would be the point such that the area under the Normal curve with mean 160 pounds and standard deviation 30 pounds to the right of w equals 0.6918.

In Excel and OpenOffice Calc this is found with

=NORMINV(1-0.6918;160;30)

and equals 144.97 pounds

(See picture 2)

and the design limit that is exceeded by 25 occupants with probability 0.0001 is 25*144.97 = 3,624.25 pounds

6 0

4 years ago