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pav-90 [236]
2 years ago
11

Algebra 1 brainilest if correct ty

Mathematics
2 answers:
mr_godi [17]2 years ago
8 0
The answer to this question is option 3
Ipatiy [6.2K]2 years ago
3 0
The answer is option 3
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Nicole’s friend runs 3/8 of a mile, but her distance is only 3/5 of Nicole’s distance. How far does Nicole run?
salantis [7]

Step-by-step explanation:

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

Let distance travelled by Nichol =x

<h2>ATQ</h2>

{:}\longrightarrow\sf {\dfrac {3}{5}}\times x={\dfrac {3}{8}}

{:}\longrightarrow\sf {\dfrac {3x}{5}}={\dfrac {3}{8}}

{:}\longrightarrow\sf 8 (3x)=5×3

{:}\longrightarrow\sf 24x=15

{:}\longrightarrow\sf x={\dfrac{24}{15}}

{:}\longrightarrow\sf x=1.6

\therefore Nichol runs 1.6miles .

4 0
3 years ago
I need help asap;):)
crimeas [40]
Newton discovered that sunlight has many colors when it passes through a prism.

I hope this helped! Mark me Brainliest! :) -Raven❤️
6 0
3 years ago
Read 2 more answers
The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest
Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)

Calculation the value from standard normal z table, we have,  

P(x < 5) =0.7287= 72.87\%

b) P( port handles 3 or more million tons of cargo per week)

P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)

Calculating the value from the standard normal table we have,

1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%

c)P( port handles between 3 million and 4 million tons of cargo per week)

P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%

P(3 \leq x \leq 4) = 23.7\%

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85  

= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85  

=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15  

Calculation the value from standard normal z table, we have,  

P( z \leq -1.036) = 0.15

\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0
2 years ago
Use order of operations to simplify
wlad13 [49]
Calculate and multiply to get
-4/(-6)+7 - 2x(-2)/-1x3+7
Next remove parentheses and calculate,
You'll get -4/-6+7 - 2x(-2)/4
Then calculate and reduce,
-4/1 - -2/2
Reduce and divide to get -4-(-1)
Remove parentheses, -4+1
And calculate to get your final answer
= -3
6 0
3 years ago
The shaded portion of the grid below represents the portion of a granola bar remaining.
Nady [450]

Answer:

A. 1%

B. 80%

C. 0.8, 8/10

Step-by-step explanation:

A. There are 100 blocks so each block is 1/100 which is 1%

B. As you can see, there are 80 blocks shaded so that would be 80/100 which is 80%

C. You can represent a percent as a decimal or a fraction

Hope this helped!

8 0
3 years ago
Read 2 more answers
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