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Natali [406]
2 years ago
13

What is equivalent to -1/4y -2 1/4y + 1/2 (4-2y) a) -3y + 2 b) -3 1/2y + 2 c) -4y + 4

Mathematics
1 answer:
Amanda [17]2 years ago
7 0

Answer:

B. -3 1/2y + 2

Step-by-step explanation:

Our expression is: \frac{-1}{4} y-2\frac{1}{4} y+\frac{1}{2} (4-2y).

Let's first distribute out that parentheses. Remember that distribution is simply taking the sum of the product of the outside term with each of the inside terms. Here, the outside term is 1/2 and the inside terms are 4 and -2y:

\frac{1}{2} (4-2y)=\frac{1}{2} *4+\frac{1}{2} *(-2y)=2-y

Now, we have:

\frac{-1}{4} y-2\frac{1}{4} y+2-y

We want to combine like terms, which means combining all the terms with y in them:

\frac{-1}{4} y-2\frac{1}{4} y-y+2=\frac{-1}{4} y-\frac{9}{4} y-\frac{4}{4} y+2=\frac{-1-9-4}{4} y+2=\frac{-14}{4} y+2=\frac{-7}{2} y+2

Remember that -7/2 can be written as the mixed number -3 1/2, so our final answer is:

-3 1/2y + 2

The answer is thus B.

<em>~ an aesthetics lover</em>

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Paraphin [41]

Answer:

<BAC = 78

<ABC = 68

Step-by-step explanation:

The remote angles theorem states that when one extends a side of a triangle, the angle formed between the extension and one of the sides of the triangle is equal to the sum of the two non-adjacent angles inside the triangle. One can apply this theorem here and state the following,

<BAC + <ABC = <ACD

Substitute,

(5y + 3) + (4y + 8) = (146)

Simplify,

9y + 11 = 146

Inverse operations,

9y + 11 = 146

     -11     -11

9y = 135

/9      /9

y = 15

Now substitute this value back into the expressions to find the numerical measurement of (<BAC) and (<ABC),

<BAC = 5y + 3

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<ABC = 4y + 8

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5 0
3 years ago
The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi
storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

V = \frac{1}{3}\pi r^{2}h

Differentiate the equation with respect to time t, such that

\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)

To differentiate the product,

Let r² = u, so that

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)

Then, using product rule

\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]

Since u = r^{2}

Then, \frac{du}{dr} = 2r

Using the Chain's rule

\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}

∴ \frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]

Then,

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

Now,

From the question

\frac{dr}{dt} = 7 m/min

\frac{dV}{dt} = 236 m^{3}/min

At the instant when r = 99 m

and V = 180 m^{3}

We will determine the value of h, using

V = \frac{1}{3}\pi r^{2}h

180 = \frac{1}{3}\pi (99)^{2}h

180 \times 3 = 9801\pi h

h =\frac{540}{9801\pi }

h =\frac{20}{363\pi }

Now, Putting the parameters into the equation

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]

236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]

708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}

708 = 30790.75 \frac{dh}{dt} + 76.36

708 - 76.36 = 30790.75\frac{dh}{dt}

631.64 = 30790.75\frac{dh}{dt}

\frac{dh}{dt}= \frac{631.64}{30790.75}

\frac{dh}{dt} = 0.021 m/min

Hence, the rate of change of the height is 0.021 meters per minute.

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Answer:

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Step-by-step explanation:

1) Carry over the decimals in each number.

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3) Carry the decimal place and count how many times you moved it over. (2=1+1) Therefore, it gives you 65.65

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